n=9. Because n+42=51. Subtract 42 from both sides and n=9
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To find what can be added to 51 to equal 180, you would subtract 51 from 180. This would give you 129. Therefore, 129 can be added to 51 to equal 180.
The consecutive integers whose sum is 51 are 16, 17, and 18.
To find the median of four numbers, you first need to arrange them in numerical order. Given that three of the numbers are 42, 51, and 52, and the median is 48, the fourth number must be 48 as well. This is because the median is the middle number in a set when arranged in ascending or descending order.
The integers are 16, 17 and 18.
Let's lay out the known information in equations, where B is the number of boys and G is the number of girls. Then we express the number B in terms of G, which is twice as much less 12, or (2G-12) B + G = 51 , and B = 2G - 12 Now, replace the B in the first equation with its value from the second equation (2G - 12) + G = 51 Remove the brackets 2G - 12 + G = 51 Add 12 to both sides 2G + G = 51 + 12 3G = 63 Divide both sides by 3 G = 21 Now, to check if we're right, Replace G in the first equation B + 21 = 51 B = 30 If that's right then 30 = 2(21) - 12 30 = 42 - 12 And it is, so we know that there are 21 girls and 30 boys in ninth grade.