number to add to 51 to equal 180 = 129180 - 51 = 129
The consecutive integers whose sum is 51 are 16, 17, and 18.
To find the median of four numbers, you first need to arrange them in numerical order. Given that three of the numbers are 42, 51, and 52, and the median is 48, the fourth number must be 48 as well. This is because the median is the middle number in a set when arranged in ascending or descending order.
Let's lay out the known information in equations, where B is the number of boys and G is the number of girls. Then we express the number B in terms of G, which is twice as much less 12, or (2G-12) B + G = 51 , and B = 2G - 12 Now, replace the B in the first equation with its value from the second equation (2G - 12) + G = 51 Remove the brackets 2G - 12 + G = 51 Add 12 to both sides 2G + G = 51 + 12 3G = 63 Divide both sides by 3 G = 21 Now, to check if we're right, Replace G in the first equation B + 21 = 51 B = 30 If that's right then 30 = 2(21) - 12 30 = 42 - 12 And it is, so we know that there are 21 girls and 30 boys in ninth grade.
The integers are 16, 17 and 18.
To find 51 percent of a number, multiply the number by 0.51. In this instance, 0.51 x 42 = 21.42. Therefore, 51 percent of 42 is equal to 21.42.
-42
The sum of the numbers between 51 and 150 is equal to 10050 - or 50 x 201 - as there are 50 lots of 201 in the sum.
33 is a two-digit number whose digits add up to 6. 60, 51, 42, 24, 15
Because 51 is greater than the sum of its proper divisors.
918 divided by 18 equal 51.
number to add to 51 to equal 180 = 129180 - 51 = 129
51
If we add 51 and 17 (51 + 17), we'd get 68 for an answer. The number 51 is 50 + 1, and the number 17 is 10 + 7, taking the units digits, 1 + 7 equals 8, and 50 + 10 equals 60. Further, 8 plus 60 is 68, so the sum of 51 and 17 is 68.
17+17+17=51
The GCF of 42 and 51 is 3.
57 36 +1 = 37 37 +2 = 39 39 +3 = 42 42 +4 = 46 46 +5 = 51 51 +6 = 57