ofwgkta
There is not a single line, but infinitely many lines, that pass through the point (-5, 0). One thing you can do is choose some random slope, then use the equation for an equation that goes through a point and has a specified slope.
A line is represented by an equation. Each solution of the equation is a point on the line, and each point on the line is a solution to the equation. So the line is just the graph of the solution set of the equation.
3
3x + 2y = 8 This is an equation. It could be the equation of a line.
You cannot define a line with a single point (a single point only defines itself). You need two points to define a line (and therefore to write the equation for it).
A linear equation is the equation of a line and that consists of an infnite number of points. What you have, in x = -4 and y = -1/3, is a single point. A single point is not a line and so there cannot be a linear equation (suitable for a line) to represent a point.
ofwgkta
True
A root of the equation that defines the line graphed exists at 0.
A vertical line can not be defined by any normal equation, because its range is a single number that gives the x-coordinate and y can have any value whatever.
-9
A single equation in two variables is, for example. Its graph is a line, and every point on the line is a solution.
It is a linear equation in the two variables x and y. A single linear equation in two variables cannot be solved for a unique pair of values of x and y. The equation is that of a straight line and any point on the line satisfies the equation.
There is not a single line, but infinitely many lines, that pass through the point (-5, 0). One thing you can do is choose some random slope, then use the equation for an equation that goes through a point and has a specified slope.
15
A line is represented by an equation. Each solution of the equation is a point on the line, and each point on the line is a solution to the equation. So the line is just the graph of the solution set of the equation.