The numbers are -30, -28 and -26.
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The set is 81, 82 and 83. There is also a set of consecutive even integers whose sum is 246. That set is 80, 82 and 84.
There are no such numbers. The only two numbers that sum to 12 and whose product is -84 are irrational, and so cannot be considered as factors of 84.
The numbers are 21 and 63.
Let the numbers be m & m+1 (consecutive) Hence their squares are m^2 & ( m + 1)^2 => m^2 & m^2 + 2m + 2 Hence Their sum is m^2 + m^2 + 2m + 1 = 85 2m^2 + 2m - 84 = 0 m^2 + m - 42 =0 Factor (m + 7)(m - 6) = 0 Hence the numbers are 6 & 7 .
Let the consecutive i9ntegers be ; n, n+1, n+2, n+3 Hence n+(n+1) +(n+2)+(n+3) = 90 Add the LHS 4n + 6 = 90 4n = 84 n = 84/4 = 21 Hence The four integers are , 21,22,23,24,