Let the consecutive i9ntegers be ; n, n+1, n+2, n+3
Hence
n+(n+1) +(n+2)+(n+3) = 90
Add the LHS
4n + 6 = 90
4n = 84
n = 84/4 = 21
Hence
The four integers are , 21,22,23,24,
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x + (x+1) + (x + 2) = 267 3x + 3 = 267 3x = 264 x = 88 Answer: 88, 89, 90
There are two consecutive even integers: 90 and 92.
29, 30 , 31
Use the equation S/2 = a + ( n - 1)d Were a = 1 d = 2 (Consecutive odd numbers havie a difference of '2' n = 90 Substitute S = 2[(1) + (90 - 1) 2[ S = 2 + 2(89)2 S = 2 + 356 S = 358
Two angles that sum to 90 degrees are called complementray angles. The term is not usually applied to three or more angles that sum to 90 degrees.