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Let the consecutive i9ntegers be ; n, n+1, n+2, n+3

Hence

n+(n+1) +(n+2)+(n+3) = 90

Add the LHS

4n + 6 = 90

4n = 84

n = 84/4 = 21

Hence

The four integers are , 21,22,23,24,

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lenpollock

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The numbers are 21, 22, 23 and 24.

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Wiki User

10y ago
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Q: What are four consecutive integers that have the sum of 90?
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