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(2x-1) + (2x+1) + (2x+3) = 117

2x - 1 + 2x + 1 + 2x + 3 = 117

6x + 3 = 117

6x = 114

x = 19

The numbers are 37, 39, and 41.

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Q: What are 3 consecutive odd integers that have a sum of 117?
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