1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 13, 14, 15, 16, 17, 19, 21, 22, 23, 25, 26, 27, 28, 29, 31, 32, 33, 34, 35, 37, 38, 39, 41, 43, 44, 45, 46, 47, 49, 50, 51, 52, 53, 55, 57, 58, 59, 61, 62, 63, 64, 65, 67, 68, 69, 71, 73, 74, 75, 76, 77, 79, 81, 82, 83, 85, 86, 87, 89, 91, 92, 93, 94, 95, 97, 98, 99
14 is deficient. It is less than the sum of it's divisors. In mathematics, a deficient number or defective number is a number n for which σ(n) < 2n. Here σ(n) is the sum-of-divisors function: the sum of all positive divisors of n, including n itself Proof.. divisors of 14 are 1,2, and 7 and 14. Now, 2n=28 and and the sum the all the divisors including 14 is 24<28
the set of real numbers
the domain is all real numbers and the range is all real numbers the domain is all real numbers and the range is all real numbers
It is deficient: It's only proper divisors are 1, 3, and 7, which sums to 11, which is less than 21.
There is no mode if all of the numbers are different.
All prime numbers are deficient.
Yes.
There are more deficient numbers.
1,2,3,4,5,7,8,9,10,11,13,14,15,16,17,19,21,21,23,25,26,27,29,31,32,33,34,35,37,38,39,41,43,44,45,46,47,49,50,51,52,53,55,57,58,59,61
No. All prime numbers are deficient.
All odd numbers with one or two distinct prime factors are deficient. Since 3 and 7 are factors of 63, it must be deficient.
no, 945 is the first abundant odd number though
No, all prime numbers are deficient.
Yes, like all prime numbers.
Yes. All prime numbers are deficient.
No, all prime numbers are deficient.
17 is a deficient number because half the sum its factors is less than 17 [(1 + 17)/2 = 9)]. All odd numbers less than 945 are deficient.