29, 30 , 31
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There are two consecutive even integers: 90 and 92.
x + (x+1) + (x + 2) = 267 3x + 3 = 267 3x = 264 x = 88 Answer: 88, 89, 90
Let the consecutive i9ntegers be ; n, n+1, n+2, n+3 Hence n+(n+1) +(n+2)+(n+3) = 90 Add the LHS 4n + 6 = 90 4n = 84 n = 84/4 = 21 Hence The four integers are , 21,22,23,24,
9 and 10
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