There are two consecutive even integers: 90 and 92.
x + (x+1) + (x + 2) = 267 3x + 3 = 267 3x = 264 x = 88 Answer: 88, 89, 90
Let the consecutive i9ntegers be ; n, n+1, n+2, n+3 Hence n+(n+1) +(n+2)+(n+3) = 90 Add the LHS 4n + 6 = 90 4n = 84 n = 84/4 = 21 Hence The four integers are , 21,22,23,24,
9 and 10
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There are two consecutive even integers: 90 and 92.
They are: 90+91+92 = 273
There are none. The only four consecutive integers totaling 90 are 21, 22, 23 and 24.
The integers are 9 and 10.
The greatest integer is 24.
The integers are -92, -91, -90 and -89.
The integers are 21, 22, 23 and 24.
x + (x+1) + (x + 2) = 267 3x + 3 = 267 3x = 264 x = 88 Answer: 88, 89, 90
Divide the sum of the two consecutive even integers by 2: 90/2 = 45. The smaller of these integers will be one less than 45 and the larger will be one more than 45, so the two consecutive even integers will be 44 and 46.
They are -10 and -9.
85, 86 and 87
-9 or -10Two consecutive negative integers that can be multiplied together with a product of 90 would be -9 and -10. A number sentence for this equation would be: -9 X -10 = 90.