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This is an ambiguous question. Are you asking for the number of combinations, or to actually list them? Since we haven't been given the 8 numbers, I assume the former. Are you asking for the number of combinations of 4 different numbers selected from the given 8, or are duplicates allowed?
The latter is kind of complicated. The number of permutations of 4 numbers selected from 8 given numbers (or any 8 things) is very easy: since each of the 4 positions in the sequence can be any of the 8, you get 8 raised to the 4th power, which is 4096. But to get the number of combinations, you have to eliminate the duplications, and the number of duplications for a permutation depends on the number of repetitions within the permutation itself. For example, the permutation (1, 2, 1, 2) has 2 pairs; you need to count the number of combinations of the 4 positions where the 1s can go, and the other 2 positions would have 2s. That number turns out to be 6, but if there is only 1 pair, as in (1, 1, 2, 3) you have 6 pairs of positions to put the 1s in, and 2 ways of ordering the 2 and the 3, so you get 12. I could go on and on.
If you don't allow duplications, then you have 8 x 7 x 6 x 5 possible permutations, which is 1,680. Each of these can be ordered 4 x 3 x 2 x 1 ways, which is 24. Dividing 1,680 by 24 gives 70 combinations
What else can I help you with?
How many combinations of 4 numbers from 8 numbers?
To calculate the number of combinations of 4 numbers from 8 numbers, you would use the combination formula, which is nCr = n! / (r!(n-r)!). In this case, n = 8 and r = 4. Plugging these values into the formula, you get 8C4 = 8! / (4!(8-4)!) = 70. Therefore, there are 70 possible combinations of 4 numbers that can be chosen from a set of 8 numbers.
How many combinations for numbers 1248?
To calculate the number of combinations for the numbers 1248, we need to consider all possible arrangements of the four digits. Since all the digits are unique, there are 4 factorial (4!) ways to arrange them. This equals 4 x 3 x 2 x 1 = 24 combinations.
How many combinations of 6 numbers are there in 10 numbers?
The answer is 10!/[6!*(10-6)!] where n! represents 1*2*3*...*n Number of combinations = 10*9*8*7*6*5*4*3*2*1/(6*5*4*3*2*1*4*3*2*1) = 10*9*8*7/(4*3*2*1) = 210
How many 4 number combinations are there using numbers 0088?
Oh honey, let me break it down for you. With the numbers 0 and 8 repeated twice, you're looking at a total of 4!/(2!2!) = 6 combinations. So, you've got 0088, 0808, 0880, 8008, 8080, and 8800. That's all she wrote, darling.
How many 10 number combinations can be made out of 10 numbers?
If you are assuming you can repeat any of the numbers then: nx where n=number of options and x= number of spaces using the formula assuming all numbers 0-9 then: 1010 10,000,000,000 is your answer. If numbers can not repeat and have to be used we use the formula: n! Where n is the number of options.Since you want 10 numbers we will do 10! 10! 10*9*8*7*6*5*4*3*2*1 362880 is your answer.
How many numbers can you make with 3 7 8 9?
14 * * * * * Wrong! There are 15. 4 combinations of 1 number, 6 combinations of 2 number, 4 combinations of 3 numbers, and 1 combination of 4 numbers.
How many combinations can you make with the numbers 2 3 6 7 and 8?
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
What are the possible combinations of numbers 0 through 9 if any numbers cannot be repeated?
There are 10 combinations of 1 number,10*9/(2*1) = 45 combinations of 2 numbers,10*9*8/(3*2*1) = 120 combinations of 3 numbers,10*9*8*7/(4*3*2*1) = 210 combinations of 4 numbers,10*9*8*7*6/(5*4*3*2*1) = 252 combinations of 5 numbers,210 combinations of 6 numbers,120 combinations of 7 numbers,45 combinations of 8 numbers,10 combinations of 9 numbers, and1 combination of 10 numbers.All in all, 210 - 1 = 1023 combinations. I have neither the time nor inclination to list them all.There are 10 combinations of 1 number,10*9/(2*1) = 45 combinations of 2 numbers,10*9*8/(3*2*1) = 120 combinations of 3 numbers,10*9*8*7/(4*3*2*1) = 210 combinations of 4 numbers,10*9*8*7*6/(5*4*3*2*1) = 252 combinations of 5 numbers,210 combinations of 6 numbers,120 combinations of 7 numbers,45 combinations of 8 numbers,10 combinations of 9 numbers, and1 combination of 10 numbers.All in all, 210 - 1 = 1023 combinations. I have neither the time nor inclination to list them all.There are 10 combinations of 1 number,10*9/(2*1) = 45 combinations of 2 numbers,10*9*8/(3*2*1) = 120 combinations of 3 numbers,10*9*8*7/(4*3*2*1) = 210 combinations of 4 numbers,10*9*8*7*6/(5*4*3*2*1) = 252 combinations of 5 numbers,210 combinations of 6 numbers,120 combinations of 7 numbers,45 combinations of 8 numbers,10 combinations of 9 numbers, and1 combination of 10 numbers.All in all, 210 - 1 = 1023 combinations. I have neither the time nor inclination to list them all.There are 10 combinations of 1 number,10*9/(2*1) = 45 combinations of 2 numbers,10*9*8/(3*2*1) = 120 combinations of 3 numbers,10*9*8*7/(4*3*2*1) = 210 combinations of 4 numbers,10*9*8*7*6/(5*4*3*2*1) = 252 combinations of 5 numbers,210 combinations of 6 numbers,120 combinations of 7 numbers,45 combinations of 8 numbers,10 combinations of 9 numbers, and1 combination of 10 numbers.All in all, 210 - 1 = 1023 combinations. I have neither the time nor inclination to list them all.
What are all the possible number combinations for 4 digit odd numbers for 7 5 4 and 8?
16
How many combinations of 4 numbers from 8 numbers?
To calculate the number of combinations of 4 numbers from 8 numbers, you would use the combination formula, which is nCr = n! / (r!(n-r)!). In this case, n = 8 and r = 4. Plugging these values into the formula, you get 8C4 = 8! / (4!(8-4)!) = 70. Therefore, there are 70 possible combinations of 4 numbers that can be chosen from a set of 8 numbers.
How many 4 number combinations using 2 3 4 5 6 7 8?
The number of combinations of 4 numbers out of 8 is 8C4= (8*7*6*5/(4*3*2*1) = 70.In a combination, the order of the numbers does not matter so that 2345, 2454, 4523 etc are all counted as 1.The number of combinations of 4 numbers out of 8 is 8C4= (8*7*6*5/(4*3*2*1) = 70.In a combination, the order of the numbers does not matter so that 2345, 2454, 4523 etc are all counted as 1.The number of combinations of 4 numbers out of 8 is 8C4= (8*7*6*5/(4*3*2*1) = 70.In a combination, the order of the numbers does not matter so that 2345, 2454, 4523 etc are all counted as 1.The number of combinations of 4 numbers out of 8 is 8C4= (8*7*6*5/(4*3*2*1) = 70.In a combination, the order of the numbers does not matter so that 2345, 2454, 4523 etc are all counted as 1.
How many 8 digit combinations can you make with 8 numbers?
If you have 8 distinct numbers and want to create 8-digit combinations using each number exactly once, there are 8! (8 factorial) possible combinations. This is calculated as 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1, which equals 40,320. Therefore, you can make 40,320 unique 8-digit combinations with 8 distinct numbers.
How many box combinations of 4 numbers from 8 numbers?
two
How many combinations of 4 in ascending order 24680?
To find the number of combinations of 4 from the set {2, 4, 6, 8, 0}, we first arrange the numbers in ascending order: {0, 2, 4, 6, 8}. Since combinations are selected without regard to order, we can use the combination formula ( C(n, k) ) where ( n ) is the total number of items to choose from and ( k ) is the number of items to choose. Here, ( n = 5 ) and ( k = 4 ), so the number of combinations is ( C(5, 4) = 5 ). Thus, there are 5 combinations of 4 numbers in ascending order from the set.
How many 4 number combinations are their using numbers 0 9?
10,000 * * * * * WRONG! That is the number of permutations, NOT the number of combinations. The number of combinations denoted by nCr = n!/[r!*(n-r)!] = 10!/[4!*6!] = 10*9*8*7/(4*3*2*1) = 210
What is the list of 5 number combinations from the following numbers 1-2-3-4-5-6-7-8?
The list of 5 number combinations from the numbers 1-2-3-4-5-6-7-8 includes various groupings. For example, some combinations are: (1, 2, 3, 4, 5), (2, 3, 4, 5, 6), (3, 4, 5, 6, 7), (4, 5, 6, 7, 8), and (1, 3, 5, 7, 8). The total number of unique combinations can be calculated using combinatorial methods.
How many 7 number combinations from 8 numbers?
To calculate the number of 7-number combinations from 8 numbers, you can use the combination formula, which is nCr = n! / r!(n-r)!. In this case, n = 8 (total numbers) and r = 7 (numbers chosen). Plugging these values into the formula, you get 8C7 = 8! / 7!(8-7)! = 8 ways. Therefore, there are 8 different combinations of 7 numbers that can be chosen from a set of 8 numbers.
