X + y
Only when X or Y = 0 That is because (x + y) squared = x^2 + 2xy + y^2 x^2 + 2xy + y^2 = x^2 + y^2 when x or y = 0
(2, -2)
No, to be linear, both the power of x and y need to be 1. Since x is squared, the power of x is 2.
X^2 + Y^2 = 36 Y^2 = 36 - X^2 Y = (+/-)sqrt(36 - X^2) A circle. X = (+/-) 6 Y = (+/-) 6
(x+y)2
(a + x^2)(b + y^2)
X + y
it is (x-y)(x-y) :)
Only when X or Y = 0 That is because (x + y) squared = x^2 + 2xy + y^2 x^2 + 2xy + y^2 = x^2 + y^2 when x or y = 0
(x + y)(x + y)(x + y)
It is a quadratic expression in the variables x and y.
2
(3x + 3y)(x + y) = 3(x + y)2
4
C2x + C2y = C2(x + y)
Your expression is this... x2 + y2/x