The first ten digits of pi are 3.141592653. If rounded to the nearest billionth, that last digit would be 4 instead of a 3.
First find the radius of the sphere using the volume formula, substitute volume for V & solve for r:V = (4/3)*PI*r3(3000*PI*m3 ) * (3/4) * (1/PI) = r3r3 = 2250 m3r = CUBE ROOT (2250 m3)r = 13.104 mThe surface area can now be calculated using the following formula:A = 4*PI*r2A = 4*PI*(13.104 m)2A = 686.83*PI m2
tangent of pi/4 = 1
Pi = 3.14159. The square root of pi = 1.7724531...
sin(pi/4) and cos(pi/4) are both the same. They both equal (√2)/2≈0.7071■
There are 100230 '3's in the first million digits of pi.
surface area. S = 4 * pi * R2 This refers to the fluence around the surface
3.141
3.1415
3.1415
45 degrees or 0.785398163. The first part is pi radians divided by 4, not quite the same thing.
There are 116 1s in the first 1000 digits of pi.
S=4*pi*r2
Suppose the plane faces of the cylinder lie in the planes that are s units above and below the centre of the sphere. Therefore, the height of the cylinder is 2*s units. Also, by Pythagoras's theorem, the radius of the cylinder, x units, is such that x^2 + s^2 = R^2 = 16 Therefore x^2 = 16 - s^2. Volume of cylinder = pi*x^2*2*s = 2*pi*(16-s^2)*s = 2*pi*(16*s - s^3) Then dV/ds = 0 implies that 2*pi*(16 - 3*s^2) = 0 so s^2 = 16/3 and so s = 4/sqrt(3) The second derivative is -2*pi*6*s which is negative and so the volume is a maximum. When s = 4/sqrt(3), Volume of cylinder = 2*pi*[16 - 16/3]*4/sqrt(3) = 2*pi*32/3*4/sqrt(3) = 256*pi/[3*sqrt(3)] = 256*sqrt(3)*pi/9 = 49.2672*pi approx. The volume of the cylinder is approx 0.5774 times that of the sphere.
all of them are in there
Pi day is when the date is the same to the first few numbers of Pi (3.14) aka March which is the 3rd month, and the 14th. (3/14)
pi-4 is the opposite and 1/4-pi is the reciprocal