The first ten digits of pi are 3.141592653. If rounded to the nearest billionth, that last digit would be 4 instead of a 3.
First find the radius of the sphere using the volume formula, substitute volume for V & solve for r:V = (4/3)*PI*r3(3000*PI*m3 ) * (3/4) * (1/PI) = r3r3 = 2250 m3r = CUBE ROOT (2250 m3)r = 13.104 mThe surface area can now be calculated using the following formula:A = 4*PI*r2A = 4*PI*(13.104 m)2A = 686.83*PI m2
tangent of pi/4 = 1
Pi = 3.14159. The square root of pi = 1.7724531...
sin(pi/4) and cos(pi/4) are both the same. They both equal (√2)/2≈0.7071■
There are 100230 '3's in the first million digits of pi.
surface area. S = 4 * pi * R2 This refers to the fluence around the surface
45 degrees or 0.785398163. The first part is pi radians divided by 4, not quite the same thing.
all of them are in there
pi-4 is the opposite and 1/4-pi is the reciprocal
Pi day is when the date is the same to the first few numbers of Pi (3.14) aka March which is the 3rd month, and the 14th. (3/14)
4
The first ten digits of pi are 3.141592653. If rounded to the nearest billionth, that last digit would be 4 instead of a 3.
4
3.14 is usually what is used for pi, along with 3.1416 which is rounded up. The first two digits are 3.1 and the first two post-decimal values are 1 and 4.
cos(a)cos(b)-sin(a)sin(b)=cos(a+b) a=7pi/12 and b=pi/6 a+b = 7pi/12 + pi/6 = 7pi/12 + 2pi/12 = 9pi/12 We want to find cos(9pi/12) cos(9pi/12) = cos(3pi/4) cos(3pi/4)= cos(pi-pi/4) cos(pi)cos(pi/4)-sin(pi)sin(pi/4) cos(pi)=-1 sin(pi)=0 cos(pi/4) = √2/2 sin(pi/4) =√2/2 cos(pi)cos(pi/4)-sin(pi)sin(pi/4) = - cos(pi/4) = -√2/2
Area = (Pi/4)*(dia2) = (Pi/4)*22 = (Pi/4)*4 = Pi sq.in = 3.1416 square inches.