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Q: What is Tan pi over 4?

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tan (pi) / 1 is zero. tan (pi / 1) is zero.

44 PI

sin(pi/4) and cos(pi/4) are both the same. They both equal (√2)/2≈0.7071■

cot2x-tan2x=(cot x -tan x)(cot x + tan x) =0 so either cot x - tan x = 0 or cot x + tan x =0 1) cot x = tan x => 1 / tan x = tan x => tan2x = 1 => tan x = 1 ou tan x = -1 x = pi/4 or x = -pi /4 2) cot x + tan x =0 => 1 / tan x = -tan x => tan2x = -1 if you know about complex number then infinity is the solution to this equation, if not there's no solution in real numbers.

1/4 pi to find the degree in terms of pi, divide the degree by 180 in this example, 45 / 180 = 1/4

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First: note 3 things about cot and tan, and note the given statement:cot = 1/tantan is cyclic with a period of Ï€, that is tan(nÏ€ + x) = tan(x)tan is an odd function, that is tan(-x) = -tan(x)tan(Ï€/4) = 1Now apply them to the problem:cot(Ï€ - Ï€/4) = 1/tan(Ï€ - Ï€/4)= 1/tan(-Ï€/4)= 1/-tan(Ï€/4)= 1/-1 = -1Thus:cot(Ï€ - Ï€/4) = -1.

tan (pi) / 1 is zero. tan (pi / 1) is zero.

As tan(x)=sin(x)/cos(x) and sin(pi/4) = cos(pi/4) (= sqrt(2)/2) then tan(pi/4) = 1

tan(theta) = 1 then theta = tan-1(1) + n*pi where n is an integer = pi/4 + n*pi or pi*(1/4 + n) Within the given range, this gives theta = pi/4 and 5*pi/4

44 PI

tan(pi/3)= sqrt(3)

Tan(Pi/5) = √(5-2*√(5)) ~= 0.7265

It is easiest to find these using the unit circle. Assuming you want exact values for sin, cos, and tan.240 degrees is equal to 4[Pi]/3 radians.cos(4[Pi]/3) and sin(4[Pi]/3) are easy to find using the unit circle,cos(4[Pi]/3) = -1/2sin(4[Pi]/3) = -(Sqrt[3])/2To find tan, you will need to do a little arithmetic. We know that tan(x) = sin(x)/cos(x), so,tan(4[Pi]/3) = sin(4[Pi]/3)/cos(4[Pi]/3)tan(4[Pi]/3) = (-(Sqrt[3])/2) / (-1/2)tan(4[Pi]/3) = ((Sqrt[3])/2) * (2/1)tan(4[Pi]/3) = ((Sqrt[3])*2) / (2*1)tan(4[Pi]/3) = (Sqrt[3]) / 1tan(4[Pi]/3) = Sqrt[3]Find the other 3 using reciprocal. This is just a little arithmetic and up to you. You know that cossec(x) = 1/sin(x), sec(x) = 1/cos(x) and cot(x) = cos(x)/sin(x).

tan 2 pi = tan 360º = 0

tan(3x)=1 3x= PI/4 x=PI/12 is the smallest positive number

The period of the tangent function is PI. The period of y= tan(2x) is PI over the coefficient of x = PI/2

1 because tan(5 pi / 4) = 1

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