-1
(4,2), (2,1),(-2,-1)
5
Perpendicular would mean that the slope of both lines have to be the same. The slope of the given line is 2, so the equation of the other line is of the form y=2x+c with c some constant. Since it is given that the intercept of the second line is -2, we know that -2 = 0.x + c which gives us c = -2 Using this, we can see that the equation of the perpendicular line is y=2x-2
y = 2/3x+4 or in the general form of sraight line equation as 2x-3y+12 = 0
2y= 3x+6
(4,2), (2,1),(-2,-1)
All points whose y-coordinate is twice its x-coordinate.
5
Points: (1, 5) and (2, 7) Slope: 2 Equation: y = 2x+3
As Anand said, the question is vague. However, two important points for any equation are the x and y intercepts. For y = 2x, the x-intercept is (0,0) and the y-intercept is (0,0). Not sure if that helps.
There are infinitely many solutions. These are coordinates of all points on the line given by the equation 2 - y = 2x - 1 or 2x + y = 3.
This is an equation of a line. There are an infinite number of solutions which are all points on the line. It is a linear equation.
If you mean: y = 2x +6 then the slope of the line is 2
y - 2x is not an equation. If that is supposed to be y = 2x then the slope is 2. Or, written as a slope, would be 2/1
Suppose the equation of the line is y = mx + c where m and c need to be determined. The slope of the line = (difference in y-coordinates of the two given points)/(difference in x-coordinates of the two given points) = (-6 - 2)/(0 - 4) = -8/-4 = 2 So m = 2 ie the equation of the line becomes: y = 2x + c where c still needs to be determined. The point (0, -6) is on the line. That is, when x = 0, y = -6. Substituting in the equation, -6 = 2*0 + c so that c = -6 and the equation of the line is y = 2x - 6
If you mean points of: (-4, 5) and (1, -5) then the equation is y =-2x-3
y=-(2/3)x + (n) where n can be any integer.