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Devin1 combination with 0 elements in it,
36 combinations with one element,
36*35/(2*1) combinations with two elements,
36*35*34/(3*2*1) with three and so on.
All in all there are 236= 68,719,476,736 combinations and I am not stupid enough to try to list them!
1 combination with 0 elements in it,
36 combinations with one element,
36*35/(2*1) combinations with two elements,
36*35*34/(3*2*1) with three and so on.
All in all there are 236= 68,719,476,736 combinations and I am not stupid enough to try to list them!
1 combination with 0 elements in it,
36 combinations with one element,
36*35/(2*1) combinations with two elements,
36*35*34/(3*2*1) with three and so on.
All in all there are 236= 68,719,476,736 combinations and I am not stupid enough to try to list them!
1 combination with 0 elements in it,
36 combinations with one element,
36*35/(2*1) combinations with two elements,
36*35*34/(3*2*1) with three and so on.
All in all there are 236= 68,719,476,736 combinations and I am not stupid enough to try to list them!
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List of all 4 digit combintions without repeating using only numbers 0-9?
Oh, dude, you wanna list out all the 4-digit combinations without repeating digits from 0 to 9? That's like 10 choose 4, which is 10! / (4!(10-4)!), which equals 210. So, there are 210 unique 4-digit combinations you can make using numbers 0 to 9 without repeating any digits. Cool, right?
How many combinations of 3 numbers are there in 32 numbers what are these combinations?
There are 32C3 = 32*31*30/(3*2*1) = 4960 combinations. I do not have the inclination to list them all.
List of 4 digit combination using number 0 through 9?
Oh, dude, you want me to list out every possible 4-digit combination using numbers 0 through 9? That's like asking me to count all the grains of sand on a beach! There are 10,000 different combinations, so you might want to grab a snack and get comfy while I rattle them off... or you could just use a combination generator online, but hey, where's the fun in that, right?
What are the 4 number combinations out of 8 numbers?
This is an ambiguous question. Are you asking for the number of combinations, or to actually list them? Since we haven't been given the 8 numbers, I assume the former. Are you asking for the number of combinations of 4 different numbers selected from the given 8, or are duplicates allowed? The latter is kind of complicated. The number of permutations of 4 numbers selected from 8 given numbers (or any 8 things) is very easy: since each of the 4 positions in the sequence can be any of the 8, you get 8 raised to the 4th power, which is 4096. But to get the number of combinations, you have to eliminate the duplications, and the number of duplications for a permutation depends on the number of repetitions within the permutation itself. For example, the permutation (1, 2, 1, 2) has 2 pairs; you need to count the number of combinations of the 4 positions where the 1s can go, and the other 2 positions would have 2s. That number turns out to be 6, but if there is only 1 pair, as in (1, 1, 2, 3) you have 6 pairs of positions to put the 1s in, and 2 ways of ordering the 2 and the 3, so you get 12. I could go on and on. If you don't allow duplications, then you have 8 x 7 x 6 x 5 possible permutations, which is 1,680. Each of these can be ordered 4 x 3 x 2 x 1 ways, which is 24. Dividing 1,680 by 24 gives 70 combinations
What are intersection sets and union sets?
Sets contain elements. The intersection of sets (represented by an upside-down 'U') is the list of elements that are common in both sets. The union of sets (represented by 'U') is the list of all the elements in the relevant sets. E.g. If A={a,b,c,d,e,f} and B={a,e,i,o,u}: The intersection of A and B is {a,e}. The union of A and B is {a,b,c,d,e,f,i,o,u} (notice how repeating elements, e.g. 'a' and 'e', are only listed once even though they occur in both sets.)
