Points: (-1, -1) and (3, 15)
Slope: 4
Points: (0, 5) and (10, -15) Slope: -2
Points: (15, 8) and (7, 3) Slope: 5/8
If you mean points of (1, 5) and (-1, -1) then the slope works out as 3
If you mean a slope of 2/5 and the point (-15, 12) then equation is 5y = 2x+90
Equation of given line: 3x + y = 15 or y = -3x + 15 Slope of given line = coefficient of x = -3 Slope of perperndicular = -1/(slope of given line) = -1 / (-3) = 1/3
Points: (0, 5) and (10, -15) Slope: -2
Points: (3, 15) and (5, 9) Slope: -3
Points: (15, 8) and (7, 3) Slope: 5/8
Points: (10, 8) and (15, 8) Slope: 0 It will be a straight horizontal line
Slop between (x1, y1) and (x2, y2) is given by: slope = y_difference / x_difference = (y2 - y1) / (x2 - x1) For (-1, -1) to (3, 15): slope= (15 - -1) / (3 - -1) = 16 / 4 =4
slope is =( 9-15 )/ (5-3) = -6/2 = -3
If you mean points of (1, 5) and (-2, -4) then the slope works out as 3
If you mean points of (1, 5) and (-1, -1) then the slope works out as 3
When given two points use the equation :- m = [y(1) - y(2)] / [ x(1) - x(2)] NB The numbers above are 'markers' , NOT the coordinates of the given points. For the points (1,1) & ( 3,15) Substitute om m = [ 15 -1] /[ 3 - 1 ] => m = [ 14] / [2] => m = 14/2 Cancel down by '2' m = 7 the slope!!!!!
The slope of the line that passes through the points (3,15) and (5,9), is -3; use the formula change in Y-axis/change in X-axis.
If you mean a slope of 2/5 and the point (-15, 12) then equation is 5y = 2x+90
The idea is to divide (difference in y-coordinates) by (difference in x-coordinates). If you mean points of (-5, 4) and (15, -4) then the slope works out as -2/5