The question does not contain an equation but an expression. An equation can have intercepts, an expression cannot.
The roots of the quadratic equation are the x-intercepts of the curve.
Yes it can. A linear equation in the form of y=mx+b can always be graphed used the x and y intercepts.
Let us say you X intercepts are -2 and 3 set up (X + 2)(X - 3) FOIL X^2 - X - 6 = 0 ----------------------- your parabolic equation
No; it means draw the curve.
The question does not contain an equation but an expression. An equation can have intercepts, an expression cannot.
The question does not contain an equation (or inequality) but an expression. An expression cannot have intercepts.
The vertex must be half way between the two x intercepts
The roots of the quadratic equation are the x-intercepts of the curve.
The 'x' and 'y' intercepts of that equation are both at the origin.
Yes it can. A linear equation in the form of y=mx+b can always be graphed used the x and y intercepts.
A circle represented by an equation x^2 + y^2 = r^2 or a circular object represented by an equation Ax^2 + By^2 = r^2 has 2 y-intercepts and 2 x-intercepts.
Draw the axes. Plot the two intercepts. Draw a line connecting the two points
Only if the discriminant of its equation is greater than zero will it have 2 different x intercepts.
3x-9y-27
Let us say you X intercepts are -2 and 3 set up (X + 2)(X - 3) FOIL X^2 - X - 6 = 0 ----------------------- your parabolic equation
One.