To find the intercepts of the equation (y = x^4 - 2x^2 - 8), we need to determine where the graph intersects the x-axis and y-axis. For the y-intercept, set (x = 0), yielding (y = -8), so the y-intercept is (0, -8). To find the x-intercepts, set (y = 0) and solve the equation (x^4 - 2x^2 - 8 = 0); this can be factored or solved using substitution methods, leading to the x-intercepts at approximately (x \approx 2.414) and (x \approx -2.414).
The question does not contain an equation but an expression. An equation can have intercepts, an expression cannot.
The roots of the quadratic equation are the x-intercepts of the curve.
Yes it can. A linear equation in the form of y=mx+b can always be graphed used the x and y intercepts.
Let us say you X intercepts are -2 and 3 set up (X + 2)(X - 3) FOIL X^2 - X - 6 = 0 ----------------------- your parabolic equation
It has a complete lack of any x-intercepts.
The question does not contain an equation but an expression. An equation can have intercepts, an expression cannot.
The question does not contain an equation (or inequality) but an expression. An expression cannot have intercepts.
The vertex must be half way between the two x intercepts
The roots of the quadratic equation are the x-intercepts of the curve.
Yes it can. A linear equation in the form of y=mx+b can always be graphed used the x and y intercepts.
The 'x' and 'y' intercepts of that equation are both at the origin.
A circle represented by an equation x^2 + y^2 = r^2 or a circular object represented by an equation Ax^2 + By^2 = r^2 has 2 y-intercepts and 2 x-intercepts.
Draw the axes. Plot the two intercepts. Draw a line connecting the two points
Only if the discriminant of its equation is greater than zero will it have 2 different x intercepts.
To find the intercepts of a quadratic equation in the standard form ( y = ax^2 + bx + c ), the y-intercept can be found by evaluating the equation at ( x = 0 ), which gives the point ( (0, c) ). For the x-intercepts, set ( y = 0 ) and solve the equation ( ax^2 + bx + c = 0 ) using the quadratic formula ( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ). The resulting values of ( x ) will give the x-intercepts.
3x-9y-27
Let us say you X intercepts are -2 and 3 set up (X + 2)(X - 3) FOIL X^2 - X - 6 = 0 ----------------------- your parabolic equation