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To find the x and y intercepts of an equation, set y to 0 to find the x-intercept (solve for x), and set x to 0 to find the y-intercept (solve for y). For example, in the equation (y = 2x + 4), the x-intercept is found by setting (y = 0), giving (x = -2), and the y-intercept is found by setting (x = 0), yielding (y = 4). If you provide specific equations, I can calculate their intercepts for you.
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How to find the x-intercepts when there is no y?
If there is no y, then the equation is of the form x = c where c is some constant value. And so the line intercepts the x axis at (c,0).
What are the x- and y-intercepts for the graph of 3x y 15?
To find the intercepts of the equation (3xy = 15), we first rewrite it as (y = \frac{15}{3x} = \frac{5}{x}). The x-intercept occurs when (y = 0), which does not exist for this equation since (y) is undefined when (x = 0). For the y-intercept, we set (x = 0), but again, this results in division by zero, indicating there is no y-intercept either. Therefore, the graph has no x- or y-intercepts.
What are the intercepts of the equation x4-2x2-8?
To find the intercepts of the equation (y = x^4 - 2x^2 - 8), we need to determine where the graph intersects the x-axis and y-axis. For the y-intercept, set (x = 0), yielding (y = -8), so the y-intercept is (0, -8). To find the x-intercepts, set (y = 0) and solve the equation (x^4 - 2x^2 - 8 = 0); this can be factored or solved using substitution methods, leading to the x-intercepts at approximately (x \approx 2.414) and (x \approx -2.414).
A linear equation cannot always be graphed by using intercepts alone?
Yes it can. A linear equation in the form of y=mx+b can always be graphed used the x and y intercepts.
What are the intercepts of this line?
To determine the intercepts of a line, you need to find where the line crosses the x-axis and y-axis. The x-intercept occurs when y = 0, and the y-intercept occurs when x = 0. If you have the equation of the line, you can substitute these values to find the respective intercepts. Please provide the equation of the line for specific intercept values.
What is the intercept of the equation y equals -x?
The 'x' and 'y' intercepts of that equation are both at the origin.
What are the x and y intercepts of the equation 5-y-3x?
The question does not contain an equation (or inequality) but an expression. An expression cannot have intercepts.
Find the x and y intercepts of 3x-2y6?
Given the linear equation 3x - 2y^6 = 0, the x and y intercepts are found by replacing the x and y with 0. This gives the intercepts of x and y where both = 0.
What is the greatest number of x- and y-intercepts that a circle can have?
A circle represented by an equation x^2 + y^2 = r^2 or a circular object represented by an equation Ax^2 + By^2 = r^2 has 2 y-intercepts and 2 x-intercepts.
How d yu find x and y intercept on a graph?
In the equation y = f(x), Put x = 0 and solve for y. Those are the y intercepts. Put y = 0 and solve for x. Those are the x intercepts.
How to find the x-intercepts when there is no y?
If there is no y, then the equation is of the form x = c where c is some constant value. And so the line intercepts the x axis at (c,0).
Find the x and y intercept of 9x54-6y?
I believe that you need an equation to solve for the x and y intercepts.
What are the intercepts of the equation x4-2x2-8?
To find the intercepts of the equation (y = x^4 - 2x^2 - 8), we need to determine where the graph intersects the x-axis and y-axis. For the y-intercept, set (x = 0), yielding (y = -8), so the y-intercept is (0, -8). To find the x-intercepts, set (y = 0) and solve the equation (x^4 - 2x^2 - 8 = 0); this can be factored or solved using substitution methods, leading to the x-intercepts at approximately (x \approx 2.414) and (x \approx -2.414).
A linear equation cannot always be graphed by using intercepts alone?
Yes it can. A linear equation in the form of y=mx+b can always be graphed used the x and y intercepts.
How do how you determine the x intercepts from an equation?
The x-intercepts are obtained by solving the equation for those value of x for which y or f(x) = 0 : where f(x) is the equation of the curve or line. If f(x) is a straight line, and the equation is in the form y = mx + c, then y = 0 gives x = -c/m For a quadratic, of the form y = ax2 + bx + c, the x-intercents are the root sof the equation, ie [-b ± sqrt(b2 - 4ac)]/(2a). The intercepts are real only when the discriminant, b2 - 4ac is non-negative.
What is the formula to find the intercepts for a quadratic equation?
To find the intercepts of a quadratic equation in the standard form ( y = ax^2 + bx + c ), the y-intercept can be found by evaluating the equation at ( x = 0 ), which gives the point ( (0, c) ). For the x-intercepts, set ( y = 0 ) and solve the equation ( ax^2 + bx + c = 0 ) using the quadratic formula ( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ). The resulting values of ( x ) will give the x-intercepts.
What are the intercepts of this line?
To determine the intercepts of a line, you need to find where the line crosses the x-axis and y-axis. The x-intercept occurs when y = 0, and the y-intercept occurs when x = 0. If you have the equation of the line, you can substitute these values to find the respective intercepts. Please provide the equation of the line for specific intercept values.
