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What is the sum of the first 22 odd numbers?
The sum of a sequence is given by sum = n/2(2a + (n-1)d) where: n = how many a = first number of sequence d = difference between terms of sequence. For the first 22 odd numbers these are: n = 22 a = 1 d = 2 → sum = 22/2(2×1 + (22 - 1)×2)) = 22² = 484 The sum of the first n odd numbers is always n²: sum = n/2(2×1 + (n-1)2) = n/2(1 + (n-1))×2 = n(n) = n²
What is the formula to find sum of n odd numbers?
The set of odd numbers is an arithmetic sequence. Let say that the sequence has n odd numbers where the first term is a1 and the last one is n. The formula to find the sum on nth terms for an arithmetic sequence is: Sn = (n/2)(a1 + an) or Sn = (n/2)[2a1 + (n - 1)d] where d is the common difference that for odd numbers is 2. Sn = (n/2)(2a1 + 2n - 2)
What is the sum of the first 45 consecutive odd numbers?
You can use the formula for the sum of an arithmetic series. Sn = (n/2)[2a + (n - 1)d].....n is the number of terms, a is the first term and d the common difference between terms. In this question, n = 45, a = 1 (as 1 is the first odd number) and d = 2 (the difference between consecutive odd numbers). Then, S(45) = (45/2)[2 + 44x2] = (45/2) x 90 = 2025.
What does d2 mean in algebra?
That would mean d times 2.
What is the sum of the first 90 consecutive odd numbers?
Use the equation S/2 = a + ( n - 1)d Were a = 1 d = 2 (Consecutive odd numbers havie a difference of '2' n = 90 Substitute S = 2[(1) + (90 - 1) 2[ S = 2 + 2(89)2 S = 2 + 356 S = 358
What is 2 n in a d?
2 n in a d is 2 = nickels in a dime.
What do d r n d 3 2 1 problem mean on a 1996 olds 98?
D=Drive, R=reverse, N=Neutral, 3, 2, & 1, are the speeds, or gears,of the transmission. So if there is a problem it is with the transmission.
How to write a program to print first n odd numbers in descending ordre?
Pick one 1: for (i=2*n-1; i>=1; i-=2) printf ("%d\n", i); 2: for (i=n; i>=1; i--) printf ("%d\n", 2*i-1); 3: for (i=0; i<n; i++) printf ("%d\n", 2*(n-i)-1);
What is the formula to find sum of n even numbers?
Sum = n/2[2Xa1+(n-1)d] where n is last number, a1 is the first number & d is the common difference between the numbers, here d=2 for the even /odd numbers. Sum = n/2 [2Xa1+(n-1)2]
How many ways can you make change for a dollar using nickels dimes andor quarters?
There are 22 ways to make change from a dollar using nickels, dimes, and quarters. 1. 4 q 2. 10 d 3. 20 n 4. 2 q , 5 d 5. 3 q , 2 d , 1 n 6. 1 q , 7 d, 1 n 7. 9 d, 2 n 8. 8 d, 4 n 9. 7 d, 6 n 10. 6 d , 8 n 11. 5 d , 10 n 12. 4 d , 12 n 13. 2 d , 16 n 14. 1 d , 18 n 15. 5 n , 3 q 16. 3 n , 1 q , 6 d 17. 7 n , 1 q , 4 d 18. 9 n , 1 q , 3 d 19. 11 n , 1 q , 2 d 20. 13 n , 1 q , 1 d 21. 14n , 3 d 22. 15n , 1 q
What is the sum of the arithmetic sequence?
The sum of an arithmetical sequence whose nth term is U(n) = a + (n-1)*d is S(n) = 1/2*n*[2a + (n-1)d] or 1/2*n(a + l) where l is the last term in the sequence.
How many different ways can you make change for a half dollar without using pennies?
Assuming nickles, dimes, and quarters, there are ten different ways to make change for a half dollar. Just enumerate the combinations... 10 n 8 n 1 d 6 n 2 d 4 n 3 d 2 n 4 d 5 d 5 n 1 q 3 n 1 d 1 q 1 n 2 d 1 q 2 q
Write a program to determine the weighted arithmetic mean using C language?
#includevoid mean(int[],int);void main(){int n,a[24];printf("Enter the number of terms to find mean\n");scanf("%d",&n);printf("Enter the numbers\n");for(i=0;i
Denominator of a rational no is greater than its numerator by 7 if the denominator is decreased by 6 and the numerator is increased by 17 the new no becomes 2 what is the original no.?
d = n + 7 and (n + 17)/(d - 6) = 2 so (n + 17)/ n + 7 - 6 = 2 (n + 17)/(n + 1) = 2 2n + 2 = n + 17 n = 15 and d = 22 Check n + 17 = 32, d - 6 = 16, 32/16 = 2 Original number is 15/22
What are the different combinations you can use to make 0.35 only using quarters dimes and nickels?
1 q 1 d 1 q 2 n 2 d 3 n 3 d 1 n 1 d 5 n 7 n
What is first difference?
In a sequence of numbers, a(1), a(2), a(3), ... , a(n), a(n+1), ... he first differences are a(2) - a(1), a(3) - a(2), ... , a(n+1) - a(n) , ... Alternatively, d the sequence of first differences is given by d(n) = a(n+1) - a(n), n = 1, 2, 3, ...
Change two thirds into a percentage?
A fraction, n/d, in percentage terms is simply (100*n) / d. In this case, n = 2 and d = 3.
