The volume of the box will be multiplied byeight.
Its area is now eight times greater than its original size. If area = L x H, then 2(L) x (4)H = 8 (original area)
The Area of a square can be written as it's side length^2, orA = s^2if the side length is doubled, then s' is 2s.A' = (s')^2A' = (2s)^2A' = 4s^2 = 4*AWhen the side length is doubled, the area increases by a factor of 4
If the length of each side is doubled, then the perimeter is also doubled.
If the diameter of a circle is quadrupled, the circle's area goes up 16 times as area is proportional to diameter squared. Remember area = pi /4 times diameter squared -------------------------------------------------------------------------- In any ratio of shapes: whatever the ratio of the lengths, the ratio of the areas is the square of that ratio. In this case, the ratio is 1:4, so the areas are in the ratio of 1²:4² = 1:16; ie as the length of the diameter is quadrupled (ratio 1:4), the area becomes 16 times bigger (1:16).
resistance is directly proportional to wire length and inversely proportional to wire cross-sectional area. In other words, If the wire length is doubled, the resistance is doubled too. If the wire diameter is doubled, the resistance will reduce to 1/4 of the original resistance.
It is quadrupled.
The surface area is quadrupled.
It would be 4 times greater.To find this algebraically: let L be the length and W the width originallyA = L x WWhen both are doubled, the equation becomesA = (2L) x (2W) = 4LWThe area of the rectangle is quadrupled if both the length and width are doubled.
When the linear dimensions of a plane figure are quadrupled, its perimeter is quadrupled, and its area is multiplied by 42 = 16 .
If both the diameter and length of a wire are quadrupled, the resistance of the wire will increase by a factor of 16. This is because resistance is directly proportional to the length of the wire and inversely proportional to the cross-sectional area of the wire, which is determined by the diameter. By quadrupling both, the resistance will increase by 4^2 = 16 times.
Assuming the wire follows Ohm's Law, the resistance of a wire is directly proportional to its length therefore doubling the length will double the resistance of the wire. However when the length of the wire is doubled, its cross-sectional area is halved. ( I'm assuming the volume of the wire remains constant and of course that the wire is a cylinder.) As resistance is inversely proportional to the cross-sectional area, halving the area leads to doubling the resistance. The combined effect of doubling the length and halving the cross-sectional area is that the original resistance of the wire has been quadrupled.
If only the length is doubled, the volume is also doubled.If only the length is doubled, the volume is also doubled.If only the length is doubled, the volume is also doubled.If only the length is doubled, the volume is also doubled.
if length is doubled then resistivity increases&when area is doubled resistivity decreases.
tripled
Doubling the length of the sides of a square results in the area being quadrupled (four times the original area).
If the length of a material is doubled, the resistivity remains the same. Resistivity is an intrinsic property of a material and is not affected by the dimensions of the material. However, the resistance of the material will double if the length is doubled, according to the formula R = ρ * (L/A), where R is resistance, ρ is resistivity, L is length, and A is cross-sectional area.