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A=b*h area = base (times) height P=2b + 2h perimeter = 2 (times) base (plus) 2 ( times) height A= b*h 12 = b*h 12/b = h let x = b h = 12/x since x = b and h = 12/x therefore P = 2x + 2(12/x)
If B is between P and Q, then: P<B<Q
The probability of A is denoted P(A) and the probability of B is denoted P(B). P(A or B) = P(A) + P(B) - P(A and B). Say P(A) = Probability of drawing a heart, which is 13/52. Say P(B) = Probability of drawing a three, which is 4/52. We now have to determine P(A and B) which is the probability of a heart and a three, which is 1/52. We now can determine the probability of drawing a heart or a three which is 13/52 + 4/52 - 1/52 = 16/52 = 4/13.
A triangle with side a: 5, side b: 8, and side c: 11 units has an area of 18.33 square units.This is not a right triangle, so it has to be calculated as two smaller right triangles, or using Heron's Formula since the side lengths are known.Here p= half-perimeter = (5 + 8 +11)/2 =12A = sqrt {p [(p - a) * (p - b) * (p - c)]}A = sqrt [ 12 (7 x 4 x 1)]A = sqrt [12 x 28]A = sqrt 336 = about 18.33
P = 5 A = 6 B = 11 Or.... P = 1 A = 30 B = 55