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What are the factors of this quadratic equation 8x2 plus 2x -1?
8x2 + 2x - 1 = 8x2 + 4x - 2x - 1 = 4x(2x + 1) - 1(2x + 1) = (4x - 1)(2x + 1)
2x - 1 9?
2x-1=9 2x=10 x=5
2x- 1 x 3?
if you mean 2x-1*3 then the answer is: 2x-3
How would you solve 2x plus 1 equals 9?
2x+1 = 9 2x = 9-1 2x = 8 x = 4
What is 2x squared plus 2x?
2x2 + 2x = 2x(x+1)
How do you represent an odd integer with a variable?
(2x-1) or (2x+1) must both be odd numbers.
what is 2x-1 x 2x-1?
(2x−1) ²
What are the factors of this quadratic equation 8x2 plus 2x -1?
8x2 + 2x - 1 = 8x2 + 4x - 2x - 1 = 4x(2x + 1) - 1(2x + 1) = (4x - 1)(2x + 1)
What is 2x-1 plus 2x-1 plus 2x-1 plus 2x-1?
8x-4
What is -1 from 2x - y?
2x - y -(-1) = 2x - y + 1
What the Anserw to 4x plus 1 equals 2x plus 5?
4x + 1 = 2x + 5 Subtract '1' frp, bpth sides Hence 4x = 2x + 4 Subtract '2x' from botbh sides 2x = 4 Divide both sides by '2' x = 2 The answer!!!!!!
Factor 2x squared plus 2x plus xy plus y?
4
Simplify Fully 6x2 plus 3x over 4x2-1?
3x(2x + 1) over (2x - 1)(2x + 1) Cancel out the 2x + 1 Answer: 3x/2x - 1
How do you factor out 2x2 -2x?
2x2- 2x = 2x*(x - 1)
4x2 plus 2x equals?
Assuming that 4x2+2x = 0: 2x (2x+1) = 0 2x = 0 or 2x+1 = 0 x = 0 or -1/2
16x4 - 1 equals?
Do you mean '16x^(4) -1 ; or ' (16 X 4 ) - 1' . Reason , the answers will be different. 16x^(4) - 1 = (2x)^(4) - 1^(4) = ((2x^(2) - 1^(2))((2x)^(2) + 1^(2)) = (2x - 1)(2x +1)((2x)^(2) + 1^(2)) = (2x - 1)(2x + 1)((2x)^(2) + 1) 2 & ( 16 X 4 ) - 1) = 64 - 1 = 63
What is the derivative of ln 1-2x?
3
