It is a binomial algebraic expression.
Its value can be evaluated if x is known.
it is a loop stuck between 4, 2, and 1
I think you mean (3x ± 1)^2 = (3x+1)(3x-1)?
9x2 + 6x + 1 = 9x2 + 3x + 3x + 1 = 3x(3x + 1) + 1(3x + 1) = (3x + 1)(3x + 1) or (3x +1)2
3x + 11
If that's -9x^3 - 3x^2 + 3x + 1, that factors to (1 - 3x^2)(1 + 3x)
2x2 + 3x + 1 = (x + 1)(2x + 1)
-3x + 1
(-3x - 1)(3x - 7)
y = 3x + 1
y = 3X - 1
If: 3x+5 = 4x+1 Then: x = 4
did you forget the = sign? I will assume 3x + 4 =1 3x = -3 x= -1
3x and x^2 - 3x + 1