simplify the expression 16+7y-8 rewrite as 7(y-8)7•y= 7y 7•8= 56 7y-56 = -49y answer= 16+ (-49y)
This is a difference of two sqaures. 49y2 - z2 = (7y - z)(7y + z)
8x - 7y = 7 (A)7x + 8y = 8 (B)7*(A): 56x - 49y = 498*(B): 56x + 64y = 648*(B)-7*(A): (64+49)*y = 64-49=> 113y = 15=> y = 15/113
73y + 144y + 49y=266y
35xy / 49y in simplest form is 5x/7
(7y + 2)(7y - 2)
simplify the expression 16+7y-8 rewrite as 7(y-8)7•y= 7y 7•8= 56 7y-56 = -49y answer= 16+ (-49y)
x+y=110 .53x+.97y=.65*110 x=110-y .53(110-y)+.97y=.65*110 .53*110-.53y+.97y=.65*110 .97y-.53y=(.65-.53)*110 .44y=.12*110 y=.12*110/.44 = 30 ml x=110-30 = 80 ml So, you need 80 ml of the 53% solution and 30 ml of the 97% solution.
100x^2-49y^2 (APEX)
25x2-49y2 is the difference of two squares and can be factored as:- (5x-7y)(5x+7y)
This is a difference of two sqaures. 49y2 - z2 = (7y - z)(7y + z)
-319
Since 98y9 is a multiple of 14y2, it is automatically the LCM of this problem.
8x - 7y = 7 (A)7x + 8y = 8 (B)7*(A): 56x - 49y = 498*(B): 56x + 64y = 648*(B)-7*(A): (64+49)*y = 64-49=> 113y = 15=> y = 15/113
4x^(2) + 28xy + 49y^(2) -> (2x)^(2) + 28xy + (7y)^2 Split into brackets ( 2x + 7y)(2x + 7y) If you applyuFOIL you will find toy come to '28xy'. The clue to this problem is to note that '4' ^ '49' are both squared numbers.