You get the largest area with a circle. Divide the perimeter by (2 x pi), then calculate the area with the formula pi x radius2.You get the largest area with a circle. Divide the perimeter by (2 x pi), then calculate the area with the formula pi x radius2.You get the largest area with a circle. Divide the perimeter by (2 x pi), then calculate the area with the formula pi x radius2.You get the largest area with a circle. Divide the perimeter by (2 x pi), then calculate the area with the formula pi x radius2.
The way to find the circumference is either 2 x pi x r, or pi x d.So rearrange the formula:circumference = 2 x pi x rcircumference / 2 x pi = rSo take the circumference, and divide it by 2 pi and you have the radius.A:Using the formula for circumference which is 2(pi)r solve for r. Now you have radius = circumference/(2pi). The formula for area of a circle is (pi)r^2. Substituting r with circumference/(2pi) you get area = pi(circumference/(2pi))^2. When you simplify you get area = circumference^2/(4pi).
The circumference C is pi times the diameter of the circle, which is twice the radiusC= pi *2rThe area A is pi times the radius squaredA = pi r2where pi = about 3.14159Example:For a radius of a 3 cmC = pi x (3 x 2) = pi x 6 = about 18.85 cmA = pi x (3)2 = pi x 9 = about 28.275 cm2
Diameter = 2 x (radius)Circumference = (pi) x (diameter) = (pi) x (2 x 72) = 144 pi = 452.39-ft (rounded)
Circumference = 2 x {pi} x radius = {pi} x diameter
You divide circumference / (2 x pi).You divide circumference / (2 x pi).You divide circumference / (2 x pi).You divide circumference / (2 x pi).
If you mean a circle: the circumference is equal to diameter x pi, or 2 x pi x radius.If you mean a circle: the circumference is equal to diameter x pi, or 2 x pi x radius.If you mean a circle: the circumference is equal to diameter x pi, or 2 x pi x radius.If you mean a circle: the circumference is equal to diameter x pi, or 2 x pi x radius.
2 x pi x 2 = 4 x pi
Circumference = (2) x (pi) x (Radius)= (2 pi) times (X + 4)= same as (2 pi X) + (8 pi)= same as [ pi (2X + 8) ]
sin x - cos x = 0sin x = cos x(sin x)^2 = (cos x)^2(sin x)^2 = 1 - (sin x)^22(sin x)^2 = 1(sin x)^2 = 1/2sin x = ± √(1/2)sin x = ± (1/√2)sin x = ± (1/√2)(√2/√2)sin x = ± √2/2x = ± pi/4 (± 45 degrees)Any multiple of 2pi can be added to these values and sine (also cosine) is still ± √2/2. Thus all solutions of sin x - cos x = 0 or sin x = cos x are given byx = ± pi/4 ± 2npi, where n is any integer.By choosing any two integers , such as n = 0, n = 1, n = 2 we can find some solutions of sin x - cos x = 0.n = 0, x = ± pi/4 ± (2)(n)(pi) = ± pi/4 ± (2)(0)(pi) = ± pi/4 ± 0 = ± pi/4n = 1, x = ± pi/4 ± (2)(n)(pi) = ± pi/4 ± (2)(1)(pi) = ± pi/4 ± 2pi = ± 9pi/4n = 2, x = ± pi/4 ± (2)(n)(pi) = ± pi/4 ± (2)(2)(pi) = ± pi/4 ± 4pi = ± 17pi/4
(i) Circumference = pi x Diameter (ii) Area = pi x Radius^2 From (i), D = C/pi R= (C/pi)/2 Substituting into (ii), Area = pi x ((C/pi)/2)^2 Simplifying: A = (C^2) / (4 x pi)
In the domain [0, 2*pi],sin is negative for pi < x < 2*picos is negative pi/2 < x < 3*pi/2 andtan is negative for pi/2 < x < pi and 3*pi/2 < x < pi.Also, the same applies for all intervals obtained by adding any integer multiple of 2*pi to the bounds.
Circumference of a circle: 2 x Pi x r (with r = the radius of the circle).Area of a circle: Pi x r x rThe circumference is 28, so:2 x Pi x r = 28r = 28 / (2 x Pi)Area = Pi x (28 / (2 x Pi)) x (28 / (2 x Pi)) = 62.4[rounded on one decimal] or more accurately (196 / Pi).
Area = (pi) x (Radius)2Radius = sqrt(area/pi)Circumference = (2 pi) x (Radius) = (2 pi) x sqrt(area/pi)Circumference = 2 x sqrt(pi x area)
If we have 2 x 4 + pi, we'll have 8 + pi, or about 11.1416 for an answer.
If circumference = 160', and circumference = 2 x pi x r, then... 160 = 2 x pi x r 80 = pi x r 80/pi = r 2(80/pi) = diameter = 50.99'
Just divide the circumference by (2 x pi).Just divide the circumference by (2 x pi).Just divide the circumference by (2 x pi).Just divide the circumference by (2 x pi).