y=a(bx) is the standard form
For a quadratic equation y=Ax2+Bx+C, the line of symmetry is given by x=-B/2ASo for the equation y=-x2+x+3, B is 1 and A is -1, so the line of symmetry isx=1/2
if its a standard linear equation in the form of y, y=mx+b then the b is the y value when x is 0. if it is a trigonometric function in the form of y=(a)sin(bx+c)+d or y=(a)cos(bx+c)+d then b is the factor of the period of the function. (the period can be found with the formula 2∏/b
Yes
Why are Quadratic equations, which are expressed in the form of ax2 + bx + c = 0, where a does not equal 0,
y=a+bx so the slope is b
This constant has the Y intercept value.
(a + x^2)(b + y^2)
It is a quadratic function which represents a parabola.
A quadratic equation.
xy + ay + ab + bx = y(x + a) + b(a + x) = y(x + a) + b(x + a) = y(x + a) + b(x + a) = (y + b)(x + a) To check, multiply out the two brackets making sure that each pair is evaluated.
y=a+bx+e sample regression model differentiate between y bar and E(Y)?
The equation ax2 + bx + c = 0, where a != 0 is called quadratic.
Your two equations are: AX + BY = A - B BX - AY = A + B + B Because you have four variables (A, B, X, Y), you cannot solve for numerical values for X and Y. There are a total of four answers to this question, solving each equation for X and Y independently. First equation: X = (A - B - BY)/A Y= (A - B - AX)/B Second equation: X = (A +2B +AY)/B Y = (BX - A - 2B)/A
Ax + Bx + C is called an algebraic expression.
A quadratic involving x and y is usually in the form 'y = ax2 + bx + c'. This form is y in terms of x, so we must rearrange it. y = ax2 + bx + c y/a = x2 + bx/a + c/a y/a = x2 + bx/a + d + e, where c/a = d + e, e = (b/a)2 y/a - e = x2 + bx/a + d y/a -e = (x + b/a)2 √(y/a - e) = x + b/a √(y/a - e) - b/a = x
x2+bx+ax+ab = x2+ax+bx+ab = x(x+a)+b(x+a) = (x+a)(x+b)