f(x)=-(1/2)x-4 What you do is find the opposite of the slope of the orriginal and just sub that in to get the equation perpendicular to the orriginal. graph that stuff son!
The slope of the perpendicular is -(1/2) .
If: y = 2/5x+10 then the perpendicular slope is -5/2x or -2.5x
+ 1/8
[ y = 2x plus or minus any number ] is parallel to it. [ y = -0.5x plus or minus any number ] is perpendicular to it.
If: 12 = 2y+x then y = -1/2x+6 So: y = 2x+4 and y = -1/2x+6 which means that they are perpendicular lines
No but y = -1/2x+3 is perpendicular to y = 2x+6
y=-2 is parallel to the x-axis and perpendicular to the y-axis.
y = -x/4
Slope of a line perpendicular to x-y=16
The slopes of perpendicular lines are negative reciprocals.[ y = -3x + 2 ] is perpendicular to [ y = x/3 plus any number ].
Parallel. They both have a slope of 4.
Neither perpendicular nor parallel
No, they are perpendicular.
It is: y = -1/2x-8
-1
It would be perpendicular to a line with the equation Y = 1/8 X.
The second equation works out as y = -1/2x+6 therefore it is perpendicular