a2 x r3 = a5, so r3 = -768/-12 = 4
a7 = a5 x r x r = -768 x 4 x 4 = -12,288
-1 to the 7th power equals -1
2 to the 7th power equals 128....
2.2 to the 7th power equals 249.4357888
It is 50000000.
Three to the 4th power divided by 3 to the 7th power equals 0.03703703703
Find the 7th term of the geometric sequence whose common ratio is 1/2 and whose first turn is 5
The 7th term is 7 x (-2)6 = 7 x 64 = 448
4096-20481024-512256-12864
a7/a10 = a10/a13 = 1/r3 where r is the common ratio. So a7 = (a10)2/a13 = -81/72 = -9/8
51
36
The sequence given is an arithmetic sequence where the first term is -29 and the common difference is 8 (calculated as -21 - (-29)). To find the 7th term, we can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ). Substituting ( a_1 = -29 ), ( d = 8 ), and ( n = 7 ), we get ( a_7 = -29 + (7-1) \cdot 8 = -29 + 48 = 19 ). Thus, the 7th term is 19.
0, 1, 1, 2, 3, 5, 8 so the 7th term is 8
every next term is 4 smaller than previous so 7th term = -23
Each term is 5 times the previous term, so termr = 5(r-1) (with term1 = 1). So the 7th term is 57-1 = 56 = 15625.
9, 12,16,21,27,34,42 42 is the 7th term 9+3=12 12+4=16 16+5=21 21+6=27 27+7=34 34+8=42, the 7th term
Each number in the sequence is the previous number divided by 4. Therefore the 7th term starting from 1024 is 0.25. The first 8 terms are: 1024, 256, 64, 16, 4, 1, 0.25 and 0.0625.