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If these are sides of a triangle then AC can have any value in the interval (3, 13).
Let f(x)=abs(x) , absolute value of x defined on the interval [5,5] f(x)= |x| , -5 ≤ x ≤ 5 Then, f(x) is continuous on [-5,5], but not differentiable at x=0 (that is not differentiable on (-5,5)). Therefore, the Mean Value Theorem does not hold.
What is the present value of 500 to be recieved 10 yrs from today if it is discount at the rate of 6 percent?
90 per cent of its initial value.
.229/.225 = 1.0178 percent error = (1.0178 - 1) times 100 to get to percent = .0178 x 100 = 1.78%