Y = 10x 10x = 40 y = 40
y = 10x
20
2xy - 10x + 3y -15 = 2x(y - 5) + 3(y - 5) =(y - 5)(2x + 3)
10x+2x-3y-4y=12x-7y
y=-10x-4
(3,21)
14
14
5x+8 = 10x+35x-10x = 3-8-5x = -5x = 1 and by substituting the value of x into the equations y = 13
Y = 10x 10x = 40 y = 40
y = 10x + 14 y-int. = 14 x-int. = -14/10 slope = 10
-2-5
X=7 y=5
If: 4y+10x = 16Then: 4y = -10x+16And: y = -2.5x+4
Substitute the values of x and y in 10x + 7y, thus: 10x + 7y = 10*9 + 7*6 = 90 + 42 = 132
If the line y = 2x+1.25 is a tangent to the curve y^2 = 10x then it works out that when x = 5/8 then y = 5/2