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If The area of a rectangle is 18 units squared and the other rectangle has area 6 units squared what would the ratio of their areas be?
ratio is 18 to 6 which is 3 to 1.
If you double the side lengths of a rectangle why is the area of the new rectangle not twice as big as the original?
Look at it this way, suppose x is one side of the rectangle and y is the other. Then the area of the rectangle would be xy. Now if you double each side of the originial rectangle you would have each side as 2x and 2y. So the area of the new rectangle would be 2x*2y or 4xy. As you can see the new area is 4 times larger than the original.
How do you find the length of a rectangle given the width and area?
the area of a rectangle = length x widthwe can rearrange this to give uslength of a rectangle = area/ width
How do you find the area of a rectangle with a triangle attached to the side?
you split your shape in half, (The rectangle and the triangle), by putting a line through it and then calculate the area of the rectangle and then calculate the area of the triangle, half the area of the triangle then add the area of the triangle and the rectangle together!Then you should have your answer!
How do you prove the formula for the area of a rectangle?
The formula for the area of a rectangle is length x breadth. In order to prove this works, work out an area of a rectangle using that formula.
What is the surface area of a cylinder that has a radius of 20mm and a height of 15mm?
The surface area is 4398.23mm2
What is the area of rectangle 20mm?
To find the area of a rectangle, you need both its length and width. Since only one dimension, 20mm, is provided, we cannot calculate the area without the second dimension. If you have the width, you can multiply it by 20mm to get the area in square millimeters.
Which is stronger in tension a 20mm diameter aluminium rod or a 15mm 15mm brass bar?
To determine which is stronger in tension, we need to consider both the material properties and the cross-sectional area. Aluminum typically has a lower tensile strength compared to brass, but the larger diameter of the 20mm aluminum rod provides a significantly greater cross-sectional area (approximately 314 mm²) compared to the smaller 15mm brass bar (approximately 176 mm²). Given this, the 20mm aluminum rod would generally be stronger in tension due to its larger area, despite the higher tensile strength of brass.
What is the formula of a irregular rectangle?
The answer depends on what aspect of a rectangle: its angles, area, side lengths, diagonals, other?The answer depends on what aspect of a rectangle: its angles, area, side lengths, diagonals, other?The answer depends on what aspect of a rectangle: its angles, area, side lengths, diagonals, other?The answer depends on what aspect of a rectangle: its angles, area, side lengths, diagonals, other?
How do their areas compare when one rectangle is twice as long as the other?
Area of a rectangle is Base(B) times Height(H).Area of smaller rectangle is BH.Area of larger rectangle is 2BH.Area of larger rectangle is twice as large as the smaller rectangle.
What is the area of a rectangle that its perimeter is 39?
156 It is impossible to calculate the area of a rectangle from its perimeter if no other dimension is known. The area of a rectangle is the product of its length and width, and the perimeter is twice the sum of its length and width.
What is the length of the base of a triangle with height 20mm and area 70mm squared?
If Area = 70mm2 and Height = 20mm Then Base = 7mm Using the formula Area = 0.5 x base x height, we can see that 70mm2= 0.5 x base x 20mm. Then, with simple algebra we can see that 70mm2/(0.5 x 20mm) = base Therefore, base = 7mm
The area of rectangle?
Rectangle area = (rectangle width) x (rectangle height)
For each triangle draw the other half of a rectangle. What does this mean?
The area of qa triangle is always half of the area of a rectangle with the same dimensions
What is the equation for finding length of rectangle?
The answer depends on what information you have about the rectangle: the area and width, or width and diagonal, area and perimeter or some other measures.
What is the area of a rectangle with length of 9 and a width f 7?
The area of ANY rectangle is (length) multiplied by (width).Armed with that knowledge, you can now find the area of that particular rectangle,as well as of any other rectangle up against which you might come in the future.
Formula for finding the area of a rectangle?
A = lw Area of a rectangle = length times width
