Area = Length times width.
We know the length, but not the width. We can solve for it using 2l + 2w = p.
(l = length, w = width, p = perimeter)
This gives us 2(40.4) + 2w = 126.6.
Solving for w gives us w = 22.9
A = lw, so area = (40.4)(22.9), which is 925.16 mm2.
The area is the length times the width. The perimeter is two times the length plus two times the width.
If the only information that you have is ... A) the figure is a rectangle, and B) the perimeter ... then you cannot calculate the area. The area of a rectangle is the length multiplied by the height., The perimeter is twice the length plus twice the height. So, a rectangle with a length of 9 units and a height of 1 until will have a perimeter of 20 units and an area of 9 square units. Another rectangle with a length of 6 units and a height of 4 units will also have a perimeter of 20 units, but it will have an area of 24 square units. To be able to calculate the area from the perimeter you need to know one of two additional things - either one of the measurements, or the ratio of the height to the length.
perimeter (P)=2(length+base) find length, area = length * base = (p/2-base)*base
If the only information that you have is ... A) the figure is a rectangle, and B) the perimeter ... then you cannot calculate the area. The area of a rectangle is the length multiplied by the height., The perimeter is twice the length plus twice the height. So, a rectangle with a length of 9 units and a height of 1 unit will have a perimeter of 20 units and an area of 9 square units. Another rectangle with a length of 6 units and a height of 4 units will also have a perimeter of 20 units, but it will have an area of 24 square units. To be able to calculate the area from the perimeter you need to know one of two additional things - either one of the measurements, or the ratio of the height to the length.+++To summarise, you can, IF you know the ratio as mentioned. Then apply that to half the perimeter to find the length and breadth.
If that's a rectangle, the perimeter is 24 inches and the area is 27 square inches.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
156 It is impossible to calculate the area of a rectangle from its perimeter if no other dimension is known. The area of a rectangle is the product of its length and width, and the perimeter is twice the sum of its length and width.
you need length and width length multiply width = area length + length + width + width = perimeter
The perimeter of a rectangle is the distance around the rectangle. The area of a rectangle is the space inside the rectangle. To calculate either one you need the length and the width of the rectangle. To calculate the area multiply the length times the width. To calculate the perimeter add the length+width+length+width (that is the distance all the way around)
Area is length times width, perimeter is twice the sum of length and breadth.
perimeter is the measure around the figure; area is the measure within the figure formula: perimeter: length+length+width+width=perimeter (for square or rectangle) area: length times width= area ( for square or rectangle)
perimeter, area =35.0,66.0 , Travis Garner Rocks!
#include<stdio.h> void main() { float length, breadth, area, perimeter; printf("Enter the length & breadth of a Rectangle\n(length breadth): "); scanf("%f %f",&length,&breadth); area=length*breadth; perimeter=2*(length+breadth); printf(" Area of the Rectangle=%0.3f\n",area); printf("Perimeter of the Rectangle=%0.3f\n",perimeter); printf("(Press ENTER to exit.)"); getch(); printf("\n"); }
The dimensions of a rectangle are the length and the width. With these two measurements , the area of the rectangle can be calculated : Area = length x width. The perimeter can also be found : Perimeter = (2 x length) + (2 x width).
the length is equal to 160,083
It is: 12 units in length