Well, honey, to maximize the area with a fixed perimeter, you want to go for a circle. So, with a perimeter of 50, you can make a circle with a radius of 7.957 and an area of approximately 199.87 square units. Just remember, circles are the real MVPs when it comes to maximizing area with a given perimeter.
Perimeter is 300 yards. This is a length and is not measured in square feet which measure area. The area of this in square feet is 150 x 300 ie 45000 sq ft
Let the length be x:- Perimeter = 2(x+25) = 122 inches 2x+50 = 122 2x = 122-50 2x = 72 x = 36 Check: 36+36+25+25 = 122 inches Area = 36*25 = 900 square inches
The perimeter of a rectangle of dimensions 50 yards x 100 yards is 300 yards.
Answer: 30 yards. Explanation: let's say it is L yards long and W yards wide. Then perimeter is 2L+2W The area is LxW=50 So Since LW=50, we substitute L=2W and write 2W(W)=2W^2=50. so W^2=50/2=25 and W=5 Now 2W=10 which is L So is it 10 yards long and 5 yards wide Let's check that. Area is 10x5=50 as desired and Length is 10 which is twice 5 as desired Now perimeter is 2L+2W=2(10)+2(5)=20+10=30 yards.
50
Perimeter of the square: 50+50+50+50 = 200m
Polhjk
No.Rectangle 5 x 10. Area = 50. Perimeter = 30.Rectangle 2 x 25. Area = 50. Perimeter = 54.
noob
The perimeter of a shape does not determine its area. The shape can be made thinner without changing its perimeter but reducing its area.
It can be 56.25 or anything less, but not more. You can't tell the area from the perimeter, and you can't tell the perimeter from the area. -- if each side is 7.5, the perimeter is 30, and the area is 56.25 -- if it's (5 by 10), the perimeter is still 30, and the area is 50 -- if it's (4 by 11), the perimeter is still 30, and the area is 44 -- if it's (3 by 12), the perimeter is still 30, and the area is 36 -- if it's (2 by 13), the perimeter is still 30, and the area is 26 -- if it's (1 by 14), the perimeter is still 30, and the area is 14
(20,5)
You can't tell the perimeter from the area.If the 50-acre area has straight sides, then the shortest possible perimeter is5,903.2 feet, or about 1.118 miles. But it can be anydistance more than that.For example . . .-- If the plot is a rectangle 1,000-ft wide by 2,178-ft long, then its area is 50 acres,and its perimeter is 8,356-ft, or about 1.583 miles.-- If the plot is a rectangle 500-ft wide by 4,356-ft long, then its area is still 50 acres,but its perimeter is 9,712-ft, or about 1.84 miles.
50 feet
50' in Length by 1' in Width...50 x 1 = 50 :: 50+50+1+1=102
50 cm2
This is solved by simultaneous equations. Perimeter = 2a + 2b = 100 where a and b are lengths of sides Area = a x b Rearranging the perimeter equation: 2a = 100 - 2b, a = 50 - b Putting this equation into the area equation: Area = (50 - b) x b = 50b - b x b Find the minimum/maximum by differentiating and setting to 0. Area' = 50 - 2b = 0, 2b = 50, b = 25 Area = 625cm sqare. when the length tends to 50, the area tends to 0. So the area can be anything from 0 to 625 cm