Well, honey, to maximize the area with a fixed perimeter, you want to go for a circle. So, with a perimeter of 50, you can make a circle with a radius of 7.957 and an area of approximately 199.87 square units. Just remember, circles are the real MVPs when it comes to maximizing area with a given perimeter.
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The square root of 50 would make a perfect square. Something around 7.something for each side of the square. That's the biggest area you could have.
The smallest? two sides of 24.99999 and two sides of 0.00001
Perimeter is 300 yards. This is a length and is not measured in square feet which measure area. The area of this in square feet is 150 x 300 ie 45000 sq ft
The perimeter of a rectangle of dimensions 50 yards x 100 yards is 300 yards.
Let the length be x:- Perimeter = 2(x+25) = 122 inches 2x+50 = 122 2x = 122-50 2x = 72 x = 36 Check: 36+36+25+25 = 122 inches Area = 36*25 = 900 square inches
Answer: 30 yards. Explanation: let's say it is L yards long and W yards wide. Then perimeter is 2L+2W The area is LxW=50 So Since LW=50, we substitute L=2W and write 2W(W)=2W^2=50. so W^2=50/2=25 and W=5 Now 2W=10 which is L So is it 10 yards long and 5 yards wide Let's check that. Area is 10x5=50 as desired and Length is 10 which is twice 5 as desired Now perimeter is 2L+2W=2(10)+2(5)=20+10=30 yards.
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