If that means (2 times 4) then the area of the square is 8*8 = 64 square cm
This is a Pythagorean triangle, ie right angled with hypotenuse = 10 feet, so the area is a half of 8 x 6 , ie 24 sqft
64 square inches
a square has 4 equal side so one side = 32/4 = 8 8 squared = 64cm
A=L(squared) (for a square only) Lets say our original square is L=2 then area is A=4 so if we double the Area A=8 then l=? L=square root of 8 therefor what ever your area is the Length of each side is the square root of the Area (on the first problem) square root of 4 is 2 therefor L is 2 Makes sence?
13
If his room is square, the sides are 8 feet.
If the area is 4, the side lengths are 2, so the perimeter is 2x4=8
The area of a regular hexagon with side lengths of 8cm is about 166.3cm2
A cube cannot have different side lengths.
32 ft.
A square with a side length of 8 units has an area of 64 square units.
Yes. For example, if the square's side length was 10, the area would be 100. If the trapezoid's two base lengths were 5 and 20, and the height was 8, the area would be 100.
A square with a side length of 8 cm has an area of 64 cm2
The square root of 128, approxiametaly 11.313
perimeter of square = 4 * side side =32/4 =8 m area of square=side * side =8* 8 =64 cm ^ 2
The area of square is : 64.0