No. The sum of the lengths of any two sides of a triangle must be greater that the third. Here 6 + 9 = 15, not > 15.
first find the unknown angle, 180o - (62o+62o) = 56o next use the law of sines to find the other side: sin 62o / 15cm = sin 56o / X Solving for x, X = 14.08 cm
The height or altitude of triangle: (2*45)/15 = 6cm Check: 0.5*15*6 = 45 square cm
15*15 = 225 square centimetres.
15cm 12cm
Isosceles
Yes
No. 7 squared plus 11 squared does not equal 15 squared.
60 cm2
Let x be the length of one of the congruent sides, then the three sides are x, x, 3x. Perimeter = x + x + 3x = 5x = 75cm => x = 15cm Thus the three sides are 15cm, 15cm, 45cm.
40mm - 15cm = 25
Using Pythagoras' theorem: 15 times the square root of 2 cm in length
25
2
Well, assuming it doesn't have any other sides, it's a scalene triangle.
No. The sum of the lengths of any two sides of a triangle must be greater that the third. Here 6 + 9 = 15, not > 15.
Length of a side of an equilateral triangle : Perimeter = 1 : 3 For example, if the length of the sides of an equilateral triangle were 5cm each, then perimeter would be three times that much - 15cm. 5 : 15 is the same as 1 : 3 when simplified. Length of a side of an equilateral triangle : Perimeter = 1 : 3 For example, if the length of the sides of an equilateral triangle were 5cm each, then perimeter would be three times that much - 15cm. 5 : 15 is the same as 1 : 3 when simplified.