(8x10) ÷ 2 = 40cm² (if units are cm)
Area of a right angle triangle is: 0.5*base*height
The area of any triangle is1/2 of (the length of the triangle's base) times (the triangle's height).
Assuming it's a right triangle: A = area, b = base, h = height A = bh/2 = (6)(8)/2 = 24
the area of a triangle is half of the base times the height the area of a triangle is half of the base times the height
The squared area of a triangle is half of its base times its perpendicular height. Or as: 0.5*base*perpendicular height = area of a triangle
Area=1/2(base*height) where either side can be the base or the height in a right triangle.
Area of a right angle triangle is: 0.5*base*height
The height has not been given but the area of the triangle is: 0.5*height*base
1/2*base of triangle*height(the perpendicular)=Area of right angled triangle
The area of a right triangle with base of 8 and height of 8 is: 32 square units. The hypotenuse is 11.31 units.
If a right triangle has an area of 81 meters an a base of 9 meters its height is: 18 meters.
Area of a triangle = base * height / 2 Therefore the base = Area * 2 / height
The area of a triangle is one half base times height. In the case of a right triangle, the base is one leg and the height is the other leg. (The two legs being separated by the right angle.)
area=(1/2)*base*height
multiply the base of the triangle by the height then halve the answer.
The relation between the height of a triangle, its base and its area is given by: Area = 0.5 * Base * Height Therefore, we have: Height = (2 * Area)/ Base.
Because the area of a triangle = 0.5*base*height