Area of a right angle triangle is: 0.5*base*height
The area of any triangle is1/2 of (the length of the triangle's base) times (the triangle's height).
Assuming it's a right triangle: A = area, b = base, h = height A = bh/2 = (6)(8)/2 = 24
The formula to calculate the area of a triangle is A = 1/2 * base * height, where A represents the area, the base is the length of the triangle's base, and the height is the perpendicular distance from the base to the opposite vertex. This formula is derived from the fact that the area of a triangle is half the product of its base and height. By plugging in the values for the base and height into the formula, you can easily determine the area of the triangle.
the area of a triangle is half of the base times the height the area of a triangle is half of the base times the height
Area=1/2(base*height) where either side can be the base or the height in a right triangle.
Area of a right angle triangle is: 0.5*base*height
The height has not been given but the area of the triangle is: 0.5*height*base
1/2*base of triangle*height(the perpendicular)=Area of right angled triangle
The area of a right triangle with base of 8 and height of 8 is: 32 square units. The hypotenuse is 11.31 units.
If a right triangle has an area of 81 meters an a base of 9 meters its height is: 18 meters.
Area of a triangle = base * height / 2 Therefore the base = Area * 2 / height
The area of a triangle is one half base times height. In the case of a right triangle, the base is one leg and the height is the other leg. (The two legs being separated by the right angle.)
area=(1/2)*base*height
multiply the base of the triangle by the height then halve the answer.
The relation between the height of a triangle, its base and its area is given by: Area = 0.5 * Base * Height Therefore, we have: Height = (2 * Area)/ Base.
Area = 0.5*base*height You will need to know the base or height then use Pythagoras theorem to find the base or height.