The area is 157 square meters.
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The major axis and the minor axis.
πab, where a and b are the lengths of the semi-major and semi-minor axes, respectively. A=pi*a*b
An oval,or more technically an ellipse, has a long ( major) axis and short (minor axis). If major axis length is a and minor length is b, then area, A is A = pi x a x b /4 where pi = 3.14 (approx)
An ellipse with centre (xo, yo) with major and minor axes a and b (the larger of a, b being the major axis) has an equation of the form: (x - xo)2 / a2 + (y - yo)2 / b2 = 1 The semi-major and semi-minor axes are half the major and minor axes. So re-arrange the equation into this form: 16x2 + y2 = 16 x2 + y2 / 16 = 1 (x - 0)2 / 12 + (y - 0)2 / 42 = 1 Giving: Centre = (0, 0) Major axis = 2 Semi-major axis = 2/2 = 1 Minor axis = 1 Semi-minor axis = 1/2
Dont know the eccentricity , but the minor axis = 39.888 cm (approx)
The area is 157 square meters rounded to the nearest whole number.
The major axes of an ellipse is its longest diameter. The minor axes, on the other hand, is the shortest diameter.
2, major & minor. (Yes, really!)
The area of an ellipse with a major axis 20 m and a minor axis 10 m is: 157.1 m2
The major axis and the minor axis.
The moment of inertia of an ellipse about its major axis (x-axis) is given by the equation I = πab^3/4, where a is the length of the semi-major axis and b is the length of the semi-minor axis of the ellipse.
pi x the minor radius x the major radius
No, the eccentricity of an ellipse tells us the shape of the ellipse, not its size. The size of an ellipse can be determined by its major and minor axes lengths, or by its area.
Area = pi*a*b where a and b are the semi-major and semi-minor axes.
It is pi*a*b where a and b are the lengths of the semi-major and semi-minor axes.
Area = pi*a*b where a and b are the semi-major and semi-minor axes.
-- the eccentricity or -- the distance between the foci or -- the ratio of the major and minor axes