5 units
A quadrilateral whose diagonals bisect each other at right angles is a rhombus. each other at right angles at M. So AB = AD and by the first test above ABCD is a rhombus. 'If the diagonals of a parallelogram are perpendicular, then it is a rhombus
always
Yes, they are perpendicular and intersect at their midpoints. The difference between diagonals in a rhombus as opposed to a rectangle or square is that the diagonals are not of equal length.
perimeter = 4S where:S is the length of any one side Like any polygon, the perimeter is the total distance around the outside, which can be found by adding together the length of each side. In the case of a rhombus, all four sides are the same length by definition, so the perimeter is four times the length of a side. Or as a formula: perimeter = 4S Sol was here!!
#1 A rhombus is a quadrilateral. #2 A rhombuses opposite sides are parallel #3 Its opposite angles are congruent. #4 Its diagonals are perpendicular bisectors of each other A rhombus is a special case of a parallelogram in that all four sides are equal in length, not just the opposite sides. A square is a special case of a rhombus in that all the angles are equal (at 90°).
15 units
84
16
Each side of the rhombus will have a length of 105/4 = 26.25 dm
16 units of length
A rhombus is a shape with 4 sides (a quadrilateral). Each side is of equal length, it could be a diamond shape, but if it's internal angles are each 90 degrees then it will be a square. Its not 390 it equals 360 .
In a rhombus each of the sides is of the same length whereas in a parallelogram, each pair of opposite sides is of the same length but the two pairs are different.
A rhombus is like a square that has had two opposite corners pulled out. That is, the side lengths are equal. Therefore the length of each side in this case is 21.
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals:Area = (1/2) * ( 12 * 7) = 42.The way this works: for a rhombus, the diagonals bisect each other (they intersect at the other's midpoint), so split this into two identical triangles BCD and BAD.The area of one of these triangles is (1/2) * Base * Height, with Base = length of BD, and Height = 1/2 length of AC.So area of one triangle = (1/2) * BD * ((1/2)*AC), and area of rhombus is 2 * area of triangle, so you have 2 * (1/2) * BD * ((1/2)*AC) = (1/2) * (BD) * (AC)
a rhombus and a parallogram are diffrent from each other beacuse the sides of a rhombus are some not equal to each other * * * * * The above answer is the wrong way around. All four sides in a rhombus must be of the same length. In a parallelogram, the pair of opposite sides must be of the same length, but each pair can be different from the other.
A quadrilateral whose diagonals bisect each other at right angles is a rhombus. each other at right angles at M. So AB = AD and by the first test above ABCD is a rhombus. 'If the diagonals of a parallelogram are perpendicular, then it is a rhombus
Since the diagonals of a rhombus are perpendicular and bisect each other, then we can use the Pythagorean theorem to find the length of the side of the rhombus. So in the right triangle, whose length of the legs are 6 and 8 centimeters, the hypotenuse length (the length of the side of the rhombus) is √(62 + 82) = √(36 + 64) = √100 = 10 cm.