A triangle cannot have four lengths!
The area of triangle is : 35.0
10+8+6 = 24 inches
it is an acute triangle.
If you have a rhombus that has been divided into four in this way, each part has an equal area. Each part is also a right-angled triangle, whose perpendicular sides are of lengths 5 and 6 inches (since these will be half the distances of the diagonals of the rhombus). Draw a sketch and you will see that this is the case. The area of a right-angled triangle is given by: A = base x height / 2 = 5 inches x 6 inches / 2 = 15 square inches Since there are four of these triangles, each having an area of 15 square inches, the total area of the rhombus is given by: A = 4 x 15 square inches = 60 square inches
An scalene triangle.
The area of triangle is : 340.0
The area of triangle is : 340.0
By definition, an equilateral triangle has all three sides of equal length! So it is impossible for it to have sides of length 10 inches and 7 inches!
If it's an equilateral triangle with 10 inch sides its height is about 8.66 inches and not 7 inches. So: area = 0.5*10*8.66 = 43.3 square inches Or: area = 0.5*10*10*sin(60) = 43.3 square inches to 1 decimal place
Area of the equilateral triangle: 0.5*10*10*sin(60 degrees) = 25 times square root of 3 which is about 43.301 square inches to 3 decimal places. If it is an equilateral triangle with 3 equal sides of 10 inches then its height would be about 8.66 inches and not 7 inches
I'm showing it with absolute proof. Equilateral triangle both side are same in size & same angel.It's given with the sides of 10 inches & height 7 inches. I don't need to count the height(7),just use side(10).The formula is=Area of a equilateral triangle="root over of 3" /4 * "a square"Now I use this formula,where "a" is 10. So the answers come=43.3,which is 44.So the Correct answer is=44 inches.* * * * *Mostly correct, but:43.3 should be rounded to 43, not 44.The units for the area should be square inches, not inches.
Using Pythagoras' theorem it is impossible for an equilateral triangle with equal sides of 10 inches to have a height of 7 inches.
A triangle cannot have four sides.
A triangle with side a: 6, side b: 5, and side c: 10 inches has an area of 11.4 square inches.
Area of the equilateral triangle: 0.5*10*10*sin(60 degrees) = 25 Times Square root of 3 which is about 43.301 square inches to 3 decimal places. If it is an equilateral triangle with 3 equal sides of 10 inches then its height would be about 8.66 inches and not 7 inches
There is a problem with your question, namely that such a triangle does not exist. An equilateral triangle with sides of length 10 would have a height of 5 * (root 3), which is approx 8.66 (not 7 as the question states). An equilateral triangle of side length 10 inches would have an area of 25*(root 3), which is approx. 43.3 inches2.
The area of triangle is : 35.0