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What is the conjugate of the complex number 7-4i?
To get the conjugate simply reverse the sign of the complex part. Thus conj of 7-4i is 7+4i
What is the complex conjugate of 2-6i?
7
What multiplies to make 3 and adds to make 2?
There are no real numbers that will answer this question, just imaginary numbers. The imaginary numbers are 1+sqrt(-2) and 1-sqrt(-2), which we normally write as 1+2i and 1-2i where i stands for the sort of (-1) (1+2i) + (1-2i) =2 (1+2i) * (1-2i) = 3 (note * stands for multiply)
What is the square-root of 4?
The square root of -4 is 2i: 2i x 2i = 4i2 = 4(-1) = -4
The roots of a quadratic equation are 3 2i and 3-2i what is the quadratic equation?
The two roots given are x = 3+2i and x = 3-2i. Therefore x - (3+2i) = 0, and x - (3-2i) = 0. This also implies that [x - (3+2i)]*[x - (3-2i)] = 0. Rewriting: (x - 3 - 2i)(x - 3 + 2i) = 0 Multiplying out: x^2 - 3x + 2ix - 3x + 9 - 6i - 2ix + 6i - 4i^2 = 0 We note that the 2ix's cancel, as well as the 6i's: x^2 - 3x - 3x + 9 - 4i^2 = 0 And finally, noting that i^2 = -1, we combine like terms and get: x^2 - 6x + 13 = 0, which is the required quadratic equation.
What is the conjugate of 7 minus 2i?
the conjugate 7-2i
Find the conjugate of 7 - 2i?
5
What is conjugation of 7-2i?
The conjugate of a complex number can be found by multiplying the imaginary part by -1, then adding the "real" part back. (-2i) * -1 = 2i, so the conjugation is 7+2i
What is the conjugate of 6-2i?
8
What is the conjugate of 6 minus 2i?
6+2i
What is the complex conjugate of -12 over 2i-6?
2i+6
The conjugate of the complex number 3 plus 2i is?
It is 3 minus 2i
If 3 - 2i is a solution to a polynomial equation is the complex conjugate 3 plus 2i also a solution yes or no?
Not necessarily, take for example the equation x^2=5-12i. Then, 3-2i satisfies the equation. However, 3+2i does not because (3+2i)^2 = 5+12i.
What is the equivalent form of 10 plus 6i and 7 plus 2i?
10 + 6i and 7 + 2i = 10 + 6i + 7 + 2i = 17 + 8i
How do you divide complex numbers?
When dividing complex numbers you must:Write the problem in fractional formRationalize the denominator by multiplying the numerator and denominator by the conjugate of the denominator.You must remember that a complex number times its conjugate will give a real number.a complex number 2+2i. the conjugate to this is 2-i1. Multiply both together gives a real number.(2+2i)(2-2i) = 4 -4i + 4i + (-4i2) (and as i2 = -1) = 8To divide a complex number by a real number simply divide the real parts by the divisor.(8+4i)/2 = (4+2i)To divide a real number by a complex number.1. make a fraction of the expression 8/(2+2i)2. multiply by 1. express 1 as a fraction of the divisor's conjunction. 8/(2+2i)*(2-2i)/(2-2i)3. multiply numerator by numerator and denominator by denominator.(16-16i)/84. and simplify 2-2i
How do you solve complex fraction?
this is a very good question. lets solve (2+3i)/(4-2i). we want to make 4-2i real by multiplying it by the conjugate, or 4+2i (4-2i)(4+2i)=16-8i+8i+4=20, now we have (2+3i)/20 0r 1/10 + 3i/20 notice that -2i times 2i = -4i^2 =-4 times -1 = 4
Which is equal to -5 plus 6i - 7-8i?
-5-7=-126i-8i=-2i-12-2i is your final answer
