The anti-derivative of X2 plus X is the same as the anti-derivative of X2 plus the anti-derivative of X.
The anti derivative of X2 is X3/3 plus an integration constant C1
The anti derivative of X is X2/2 plus an integration constant C2
So the anti-derivative of X2+X is (X3/3)+(X2/2)+C1+C2
The constants can be combined and the fraction can combined by using a common denominator leaving
(2X3/6)+(3X2/6)+C
X2/6 can be factored out leaving
(X2/6)(2X+3)+C
Hope that helps
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negative cotangent -- dcot(x)/dx=-csc^2(x)
X = √63
Assuming you mean x squared plus 5x squared... the answer is 6x squared.
X + y
x squared +6x +5 is a quadratic expression that can be factored as (x+1)(x+5)