(1 - x4y4) = (1 + x2y2)*(1 - x2y2) = (1 + x2y2)*(1 + xy)*(1 - xy)
The GCF is xy
Half of XY...
If you mean: xy2/xy then it can be simplified to y
The general multiplicative inverse of xy is y-1x-1. The additive inverse is -xy
(y-2) (x+4)
(1 - x4y4) = (1 + x2y2)*(1 - x2y2) = (1 + x2y2)*(1 + xy)*(1 - xy)
x=y+3t Original formula: y2 -xy = 9t2 -3xt (assumes you meant "9 times t2 " and not (9t)2 ) y2 = xy +9t2 -3xt y2 - 9t2 = xy - 3xt (y-3t)(y+3t) = x(y-3t) (y-3t) = x
(xy - 7)(x^2y^2 + 7xy + 49)
x6 - y6 = (x3)2 - (y3)2 = (x3 + y3) (x3 - y3) = (x + y)(x2 - xy + y2)(x - y)(x2 + xy + y2)
To solve the given terms is almost impossible in the absence of any plus, minus and equality signs.
xy + xy = 2xy
XY
It is an expression in the form of: xy+7
It is difficult to be certain. Limitations of the browser used by Answers.com means that we cannot see most symbols. Please resubmit your question spelling out the symbols as "plus", "minus", "equals". If the question is about xy = 7, then it is an equation of an inverse relationship. This is NOT the same as an inverse equation.
The answer depends on whether xy are commutative numbers or operators in a permutation group.
The GCF is xy