As a square has right angles, the diagonal forms a right triangle with two of the sides of the square. Therefore use Pythagoras: diagonal² = side² + side² → diagonal² = 2side² → diagonal = side × √2 Therefore to find the length of the diagonal of a square, multiply the side length of a square by the square root of 2.
The side lengths of a square with a diagonal of 16 is: 11.31.
The square's diagonal is 11.314 cm
The diagonal of a square = the length of one side x the square root of 2 (approx 1.414)
The diagonal is 14.142 feet.
Use Pythagoras: Diagonal² = √(2 × sidelength²) → diagonal = side_length × √2 → diagonal = 12 × √2 ≈ 17.0 units
Use Pythagorean theorem (a2 + b2 = c2). The diagonal measurement is just under 17.122 + 122 = c2144 + 144 = c2288 = c2c = SQRT288 = 16.9705627484771
Since a 12x12 tile is one square foot, then 38 12x12 tiles will cover 38 square feet.
I assume that you refer to a 12 ft x 12 ft 8 in square. The length of the diagonal is determined easily suing Pythororas's therem: Diagonal = sqrt[122 + (128/12)2] feet = sqrt(304.4... ) ft = 17.448 ft approx.
13.2077 cm (12x12) + (12x12)= 288 square root of 288 = 13.2077...
The diagonal of a square is not perpendicular to its side. The diagonal of a square will separate the square into two triangles. The diagonal goes from one corner to the opposite corner. Because it is a square, the diagonal and a side of the square will always form a 45-degree angle.
As a square has right angles, the diagonal forms a right triangle with two of the sides of the square. Therefore use Pythagoras: diagonal² = side² + side² → diagonal² = 2side² → diagonal = side × √2 Therefore to find the length of the diagonal of a square, multiply the side length of a square by the square root of 2.
144 square feet
144 square feet
Since each 12x12-inch tile is one square foot, you will need 750 of them.
A 12x12 inch paver is one square foot. So you would need 240 square feet.
It is 144 square feet.