I assume that you refer to a 12 ft x 12 ft 8 in square.
The length of the diagonal is determined easily suing Pythororas's therem:
Diagonal = sqrt[122 + (128/12)2] feet = sqrt(304.4... ) ft = 17.448 ft approx.
The diagonal measurement of an 8 ft square is: 11.31 feet.
The diagonal of a rectangle 8 feet by 12 feet is √208 feet, or about 14 feet 5.06 inches.
46.648 ft
7 times the square root of 2 feet
Use Pythagoras' therorem to find the diagonal of the rectangle which is 12 times the sq rt of 13
The diagonal measurement for 36 feet by 36 feet is 50.91 feet.
Diagonal = 36.9 feet
The diagonal is 45.61 feet.
The diagonal measurement of an 8 ft square is: 11.31 feet.
235 Feet
116.6 feet
36.8782 ft
The diagonal of a rectangle 8 feet by 12 feet is √208 feet, or about 14 feet 5.06 inches.
25.6125 (rounded)
46.648 ft
18 ft Diagonal of a square is the square root of 2, times the side.
14.42 feet.