I assume that you refer to a 12 ft x 12 ft 8 in square.
The length of the diagonal is determined easily suing Pythororas's therem:
Diagonal = sqrt[122 + (128/12)2] feet = sqrt(304.4... ) ft = 17.448 ft approx.
The diagonal measurement of an 8 ft square is: 11.31 feet.
46.648 ft
7 times the square root of 2 feet
Use Pythagoras' therorem to find the diagonal of the rectangle which is 12 times the sq rt of 13
The answer depends on the measurement units used for "12x12": feet, metres, yards or some exotic measure? Without that information the question cannot be answered.
The diagonal measurement for 36 feet by 36 feet is 50.91 feet.
The diagonal is 45.61 feet.
Diagonal = 36.9 feet
The diagonal measurement of an 8 ft square is: 11.31 feet.
235 Feet
116.6 feet
36.8782 ft
To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem. For a rectangle measuring 16 feet by 38 feet, the diagonal (d) can be calculated as (d = \sqrt{(16^2 + 38^2)}). This results in (d = \sqrt{(256 + 1444)} = \sqrt{1700} \approx 41.23) feet. Therefore, the diagonal measurement is approximately 41.23 feet.
25.6125 (rounded)
46.648 ft
18 ft Diagonal of a square is the square root of 2, times the side.
14.42 feet.