The length of a square with an area of 81 would be 9.
Given the length of the diagonal of the square ... call it 'D units'. The area of the square is (1/2 D2) (same units)2.
As no shape has been given for the area it is impossible to given the length of the diagonal - the diagonal can be ANY length greater than 0 (assuming you can define what diagonal means for the shape). If you are referring to a square with an area of 11 square inches then: Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 → diagonal² = 2 × area → diagonal = √(2 × area) = √(2 × 11 sq in) = √22 in ≈ 4.69 in If you mean an 11 inch square, ie a square with 11 inches along each side: Use Pythagoras: Diagonal² = √(2 × sidelength²) → diagonal = side_length × √2 → diagonal = 11 in × √2 ≈ 15.6 in
If diagonal is 10 then each side is sqrt 50 (Pythagoras) and area is sqrt 50 x sqrt 50 ie 50
A square with a side length of 9 units has an area of 81 square units.
The diagonal length of a square with a 900 square foot area is: 42.43 feet.
The area of square is : 11664.0
The length of a square with an area of 81 would be 9.
The diagonal of a square whose area is 36 is the square root of 72, or about 8.49. Since the area of a square is side(squared), then the sides are each 6. Then since a(squared) + b(squared) = c(squared), for a triangle (the diagonal), you get the square root of 72.
The area is 72 square units. Explanation: the diagonal,d, is the hypotenuse of a rt. triangle whose legs are both s, the side of the square, so d2= s2 + s2 = 2s2 Therefore , the area of the square , s2 = d2/2 = (12)2/ 2 = 144/2 = 72.
If you are given the area of the square, then the length of each side is the square root of the area. If you are given the length of the diagonal of a square, then the lenght of each side is equal to the length of the diagonal divided by the square root of 2. l=sqrt(a) l=d/[sqrt(2)] l=length of side, d=diagonal, a=area, sqrt means square root
Given the length of the diagonal of the square ... call it 'D units'. The area of the square is (1/2 D2) (same units)2.
3.54Improved Answer:-Let a side of the square be x and use Pythagoras' theorem to find its length:-2x2 = 25x = sqrt of 12.5Area = sqrt 12.5*sqrt 12.5 = 12.5So the area of the square = 12.5 square units
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The diagonal is 14 inches.
If the area of a square is 100, then its side length is 10. If we draw in a diagonal, then we know by the Pythagorean formula that the diagonal's length is sqrt(10^2 + 10^2) = sqrt(200) = 10*sqrt(2).The square root of 2 is approximately 1.414, so the diagonal's length is approximately 10*1.414 =14.14* The diagonal of any square is the side length times (sq rt 2).
Using Pythagoras' theorem which says that the square on the hypotenuse (in this case the diagonal) is equal to the sum of the squares on the other two sides (which in the case of a square would be equal in length). so if the diagonal measured 10 units, the square on the diagonal would be 100 square units. And as this = 2*the squares on the other sides, the square on one side would be 100/2 = 50 square units. As a square has sides of equal length the square on one side is actually the area of the square. i.e. the area of a square with a diagonal of 10 units is 50 square units. or generically the area of a square with a diagonal of length 'x' = (x2)/2