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This is when two perfect squares(ex.) [x squared minus 4] a question in which there are two perfect squares. you would find the square root of each. then it depends on what kind of math your doing.

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16y ago

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In a difference of squares problem terms must be perfect squares?

coefficient


In a difference of squares problem both terms must be what squares?

Perfect


What is the formula to a factor a difference of perfect squares?

a^(2) - b^(2) = ( a - b)( a + b) NB Noter the different signs. NNB Note the ADDITION of perfect squares ' a^(2) + b^(2) ' does NOT factor.


Is 2011 the difference of 2 perfect squares?

Yes. 1,012,036 (which is 1006 squared) 1,010,025 (which is 1005 squared)


How do you identify a difference of two squares?

The word "difference" implies subtraction. The word "squares" implies a perfect square term or number. To recognize the "difference of squares" look for 2 perfect square terms, one being subtracted from the other. Ex. x2 - 16. "x" is being squared and 16 is a perfect square. They are being subtracted. Factors: (x+4)(x-4)


How can you two perfect squares for a given integer?

The proposition in the question is simply not true so there can be no answer!For example, if given the integer 6:there are no two perfect squares whose sum is 6,there are no two perfect squares whose difference is 6,there are no two perfect squares whose product is 6,there are no two perfect squares whose quotient is 6.


What is the solution of the difference between first two perfect squares that end with 9?

The smallest perfect squares that end with 9 are 9 (the square of 3) 49 (the square of 7). Their difference is 40.


What is difference of 2 squares?

The difference of 2 squares ca n be expressed as: x2 - y2


Why is the product of two perfect squares always a perfect square?

The product of two perfect squares is always a perfect square because a perfect square can be expressed as the square of an integer. If we take two perfect squares, say ( a^2 ) and ( b^2 ), their product can be written as ( a^2 \times b^2 = (a \times b)^2 ). Since ( a \times b ) is an integer, ( (a \times b)^2 ) is also a perfect square, confirming that the product of two perfect squares yields another perfect square.


What is an expression that contains two perfect squares with one subtracted from the other?

Difference


What is the answer of the difference between first two perfect squares that end with 9?

40


How do you write 0 as the difference of two squares?

How can you have 0 as the difference of two squares? 5^2-5^2?