The browser that is used for submitting questions does not permit many mathematical symbols. It is therefore not possible to be sure what the question was. For a quadratic equation of the form y = ax^2 + bx + c, where a, b and c are real numbers and a is non-zero, the discriminant is b^2 – 4ac.
Note that the equation must first be written with descending powers of x so as to identify a, b and c.
The discriminant is 0.
It is a quadratic equation and its solutions can be found by using the quadratic equation formula.
If you mean: 9x2-36x+16 then it is not a perfect square because its discriminant is greater than zero
Discriminant = (-10)2 - 4*5*(-2) = 100 + 40 > 0 So the quadratic has two real roots ie it crosses the x-axis twice.
No because the discriminant of the given quadratic expression is less than zero.
The discriminant is 0.
The discriminant is 0.
2x2 + 10x - 3 The discriminant is defined as b2 - 4ac, so for this function b=10, a=2, and c=-3 So the discriminant is 100-4*2*-3 = 124
The discriminant is 900.
The discriminant of a quadratic ax2 + bx + c is b2 - 4ac; thus: the discriminant of -9x2 + 6x + 14 is 62 - 4 x -9 x 14 = 540
It is: 0
9x2 - 28x + 20 = 9x2 - 18x - 10x + 20 = 9x(x - 2) - 10(x - 2) = (9x - 10)*(x - 2)
It is a quadratic equation and its solutions can be found by using the quadratic equation formula.
It is 4x^2 + 10x - 1
If you mean: 9x2-36x+16 then it is not a perfect square because its discriminant is greater than zero
Equation: x^2 +2kx +10x +k^2 +5 = 0 Using the discriminant: (2k +10)^2 -4*1*(k^2 +5) = 0 Solving the discriminant: k = -2
It is zero because: 182-4*9*9 = 0