The distance is 15, because -6 is 6 spaces away from zero and 9 is 9 spaces away from zero. You add the two distances to find the distance between the two numbers.
The absolute value of |l-6| is the distance between the number 'l' and the number 6 on the number line, regardless of the direction. If l is greater than 6, the absolute value of |l-6| is l-6. If l is less than 6, the absolute value of |l-6| is 6-l. In either case, the absolute value function ensures that the result is always non-negative.
No, between 8 and 9, very close to eight.
The square root of 29 is an irrational number, close to (but not equal to) 5.385; on a number line, this is a point between 5 and 6 closer to 5 than 6. The number can also be represented as a continued fraction. You can find a link to an image of this representation below.
Points: (-6, 1) and (-2, -2) Distance: 5 units
If d is the distance between them, then d2 = (-6 -10)2 + (1 - (-8))2 = (-16)2 + 92 =256 + 81 = 337 so d = sqrt(337) = 18.36
14
6
-3
six units
The distance formula is the final position minus the initial. So: 6 - (-3) = 9
-6
26 here is why: on the number line the distance between 14 and 8 is 6, so we need a number whose distance between 14 and that number is 12.. so 12+14=26 and that works
To find the point on the number line that is one-third of the way from A (31) to B (6), first calculate the distance between A and B, which is 31 - 6 = 25. One-third of that distance is 25 / 3 ≈ 8.33. Subtract this value from A: 31 - 8.33 ≈ 22.67. Thus, the point is approximately 22.67 on the number line.
The distance between the numbers 4 and -6 on a number line is calculated by taking the absolute difference of the two values. This is done using the formula |a - b|, where a and b are the two numbers. Thus, the distance is |4 - (-6)| = |4 + 6| = |10| = 10. Therefore, the distance between 4 and -6 is 10 units.
5.7, on a number line, is located in between 5 and 6.
6/10 of the distance from 0 to 1.
6 - the same as from 4 to 10.