The distance is 15, because -6 is 6 spaces away from zero and 9 is 9 spaces away from zero. You add the two distances to find the distance between the two numbers.
Well, darling, the absolute value of |x| is the distance between x and 0 on the number line. So, in this case, the absolute value of |l-6| is just the distance between l and 6. Simple math, honey, it's just 6 units away from l.
No, between 8 and 9, very close to eight.
The square root of 29 is an irrational number, close to (but not equal to) 5.385; on a number line, this is a point between 5 and 6 closer to 5 than 6. The number can also be represented as a continued fraction. You can find a link to an image of this representation below.
Points: (-6, 1) and (-2, -2) Distance: 5 units
If d is the distance between them, then d2 = (-6 -10)2 + (1 - (-8))2 = (-16)2 + 92 =256 + 81 = 337 so d = sqrt(337) = 18.36
14
6
-3
six units
The distance formula is the final position minus the initial. So: 6 - (-3) = 9
-6
26 here is why: on the number line the distance between 14 and 8 is 6, so we need a number whose distance between 14 and that number is 12.. so 12+14=26 and that works
5.7, on a number line, is located in between 5 and 6.
6/10 of the distance from 0 to 1.
6 - the same as from 4 to 10.
-8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 There is a distance of 12.
Using the distance formula for a line segment it works out as 9