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How do you find the equation of a line that has a gradient of 2 and passes through the point 3 and 2?
Wiki User
∙ 13y ago
y=mx+c
The equation of the line is y = mx + c where
m is the gradient of the line and c is the y-intercept
That is, y = 2x + c where c is a constant to be determined.
Since the point (3, 2) is on the line,
2 = 6 + c so that c = -4
So the line is y = 2x - 4
Wiki User
∙ 13y ago
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What does y equals -2x-4 equal?
2
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-40
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What is the point-slope form of the equation of a line that passes through the point (1 4) and has a slope of and minus3?
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A line passes through the points 2 -2 and 1 5 find the equation of the line?
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What does y equals -2x-4 equal?
2
How do you write an equation for a given line that passes through a given point?
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How do you write an equation for a line that passes through point and is parallel to the given line?
Both straight line equations will have the same slope or gradient but the y intercepts wll be different
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a line passes through the point (-2,5) and through the point (3,6) write the equation of the line?
sda
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The general equation of a line isy = mx + cIf the gradient is 3 then m = 3 so thaty = 3x + cSince the point (4,1) lies on this line, these coordinates must satisfy the equation.So 1 = 3*4 + cie c = -11Therefore, the equation is y = 3x - 11
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414
