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Determine whether the graphs of the equations are parallelperpendicular or neither?
Base on the slope of two linear equations (form: y = mx+b, where slope is m): - If slopes are equal, the 2 graphs are parallel - If the product of two slopes equals to -1, the 2 graphs are perpendicular. If none of the above, then the 2 graphs are neither parallel nor perpendicular.
What is the perpendicular distance from the point of 2 4 to the straight line of y equals 2x plus 10 on the Cartesian plane?
The perpendicular distance from (2, 4) to the equation works out as the square root of 20 or 2 times the square root of 5
What is the perpendicular ditance from the point 7 5 to the line 3x plus 4y -16 equals 0?
If you mean the perpendicular distance from the coordinate of (7, 5) to the straight line 3x+4y-16 = 0 then it works out as 5 units.
What is the equation that represents the line perpendicular to y equals -3x plus 4 and passing through the point -1 1?
y = 1/3x+4/3
How would you find the perpendicular distance from the point 7 5 to the line 3x plus 4y -16 equals 0 on the Cartesian plane?
Equation of line: 3x+4y-16 = 0 or y = -3/4x+4 Slope of line: -3/4 Slope of perpendicular line: 4/3 Perpendicular equation: y-5 = 4/3(x-7) or 3y = 4x-13 Both equations intersect at: (4, 1) Perpendicular distance from (7, 5) to (4, 1) = 5 units using distance formula
The lines given by the equations y equals 2x and y equals 0.5x are?
Neither perpendicular nor parallel
Is y equals -4x plus 1 perpendicular?
It is perpendicular to a family of other linear equations: of the form 4y = x + c
What is the perpendicular distance from the point 3 -4 on the Cartesian plane to the line 5x -2y equals 3 rounding off work to three decimal places?
Equation: 5x-2y = 3 Perpendicular equation: 2x+5y = -14 Both equations intersect at: (-13/29, -76/29) Perpendicular distance to 3 decimal places: 3.714
What is the perpendicular distance from the point 2 4 to the line y equals 2x plus 10 on the Cartesian plane?
Known equation: y = 2x+10 Perpendicular equation: 2y = -x+10 Both equations intersect at: (-2, 6) Distance from (2, 4) to (-2, 6) is sq rt of 20 using the distance formula
What is the perpendicular distance from the point 4 -2 to the line 2x -y -5 equals 0 showing key stages of work?
Points: (4, -2) Equation: 2x-y-5 = 0 Perpendicular equation: x+2y = 0 Equations intersect at: (2, -1) Perpendicular distance is the square root of: (2-4)2+(-1--2)2 = 5 Distance = square root of 5
What is the perpendicular distance from the point 4 -2 to the line 2x -y -5 equals 0?
From the given information the perpendicular line will form an equation of 2y = -x and both simultaneous line equations will intersect each other at (2,-1) and so distance from (4, -2) to (2, -1) is the square root of 5 by using the distance formula.
What is the perpendicular distance from the point 2 4 to the line y equals 2x plus 10?
Known equation: y = 2x+10 Perpendicular equation through point (2, 4): 2y = -x+10 Both equations intersect at: (-2, 6) Perpendicular distance from (2, 4) to (-2, 6) is 2 times square root of 5 by using the distance formula
What is the perpendicular distance from the point 7 5 to the staight line equation 3x plus 4y -16 equals 0 showing key stages of work?
Equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Both equations intersect at: (4, 1) Perpendicular distance: square root of (7-4)2+(5-1)2 = 5
What is the perpendicular from the point 2 4 to the line y equals 2x plus 10 on the Cartesian plane with work shown?
If you mean the perpendicular distance then it is worked out as follows:- Equation: y = 2x+10 Perpendicular slope: -1/2 Perpendicular equation: y-4 = -1/2(x-2) => 2y = -x+10 The two equations intersect at: (-2,6) Perpendicular distance is the square root of: (-2-2)2+(6-4)2 = 4.472 to 3 d.p.
Are 4y-3x equals 1 and 2y equals 3 over 2x -14 perpendicular or parallel?
They are parallel because the slope has the same value in both equations.
What is the perpendicular distance from the point 7 and 5 to the straight line equation of 3x plus 4y minus 16 equals 0?
Straight line equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Point: (7, 5) Equations intersect: (4, 1) Perpendicular distance: square root of [(7-4)2+(5-1)2] = 5
What is the perpendicular distance from the coordinates of 7 and 5 to the straight line of 3x plus 4y -16 equals 0 showing key stages of work?
Points: (7, 5) Equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Equations intersect at: (4, 1) Length of perpendicular line: 5
