y=mx+c
where x and y are variables, m is the gradient (or slope) and c is the intercept on y (axis).
that is the general equation of a straight line. if you had given some coordinates for the points one could extrapolate from that to find the full equation. since you have not, one cannot.
y=-x
Y=4x+3
y = 2/3x+4 or in the general form of sraight line equation as 2x-3y+12 = 0
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
Gradient = (4 + 2)/(0 + 2) = 6/2 = 3 So the equation is (y + 2) = 3(x + 2) or y = 3x + 4
The equation is x = 2
Points: 0 2 and 6 0 Equation: y = -1/3x+2
x = 2
The formula for a line is: Y = mX + b
Points: (2, 2) and (3, 1) Slope: -1 Equation: y = -x+4
If you mean of points of (3, -4) and (5, 1) then the equation works out as 2y=5x-23
6666
y = 4
y = -1.125x + 2.25
Points: (1, 5) and (2, 7) Slope: 2 Equation: y = 2x+3
Points: (0, 3) and (5, 23) Slope: 4 Equation: y = 4x+3
y = 2.25x -6