Points: (2, 5) and (4, 3)
Slope: -1
Equation: y = -x+7 in slope-intercept form
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If you want to write the slope-intercept form of the equation of the line passing through the given points, then use the two points to find the slope of the line. After that, use the slope and one of the points to find the y-intercept. For instance,
m = (5 - 3)/(2 - 4) = 2/-2 = -1(the slope)
y = mx + b (replace m with -1, and (x, y) with (4, 3))
3 = -1(4) + b
3 = -4 + b (add 4 to both sides)
7 = b
Thus, y = -x + 7 is the equation of the line passing through (2, 5) and (4, 3).
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.
If you mean points of (-4, 2) and (4, -2) Then the straight line equation works out as 2y = -x
If the line passes through (5, 2) and (5, 7), then the x value stays constant for those two points, and since it is a line, the x value stays constant for the whole line, so the equation of the line isx = 5
If the points are (1,5) and (0,0) y = 5x
Points: (0. 5) and (2, 3) Slope: -1 Equation: y = -x+5
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
If you mean points of (-4, 2) and (4, -2) Then the straight line equation works out as 2y = -x
It is y = 2.
Y= -3x + 8
If the line passes through (5, 2) and (5, 7), then the x value stays constant for those two points, and since it is a line, the x value stays constant for the whole line, so the equation of the line isx = 5
3
If you mean points of (2, -2) and (-4, 22) then the equation is y = -4x+6
The equation for the given points is y = x+4 in slope intercept form
Answer this question…y = 2x + 6
Slope-intercept form